3 quick questions.

About question 3
I’ll mark even as E, odd – as O.
(1)
x(y+5) – even.
Means that
a. x and y+5 are both E, making y O
b. x-E, y+5=O, making y-E
c. x-O, y+5=E, making y O
x can be as O as E – INSUFFICIENT

(2)
6y^2+4y+25 = E
Means that 6y^2+4y = O
factorizing y we get y(6y+4) = O
6y+4 is obviously E, this means that y is O
But nothing about x….– INSUFFICIENT


(1) and (2)
From (2) we know that y is Even.
From (1) we know that to make x(y+5) even x can be as E (from a.) as O (from c.)
So, INSUFFICIENT

Answer is E.
Here E doesn’t mean Even

About the 1st question:
From the table is can deduce that to make 130 cents we should by only 1 combination - 2*23 cents+4*21cents=130 cents.
Because from the main statement we know that we have nly 6 pencils.

Thats why (2) in SUFFicient making B the right answer

About 2nd question - no idea, too

Question 3

using 2)
The quadratic equation will be even under following condition
6y2 (always even) + 25 (odd) + 41y (this needs to be odd, hence y cannot be even)
So get y is odd

From 1) x(y+5)
y+5 is even hence even . (x, even or odd) will give x(y+5) as even

hence, even using both the statement you it is not possible to determine if x is odd or even hence E

4meonly wrote:About the 1st question:
From the table is can deduce that to make 130 cents we should by only 1 combination - 2*23 cents+4*21cents=130 cents.
Because from the main statement we know that we have nly 6 pencils.

Thats why (2) in SUFFicient making B the right answer

About 2nd question - no idea, too

But it does not say we have 6 pencils in the stem, it just says she bought some pencils we do not know she bough 6 pencils until statement 1.

sharad wrote:Question 3

using 2)
The quadratic equation will be even under following condition
6y2 (always even) + 25 (odd) + 41y (this needs to be odd, hence y cannot be even)
So get y is odd

From 1) x(y+5)
y+5 is even hence even . (x, even or odd) will give x(y+5) as even

hence, even using both the statement you it is not possible to determine if x is odd or even hence E

Thanks for this. Made sense.

4meonly wrote:About question 3
I’ll mark even as E, odd – as O.
(1)
x(y+5) – even.
Means that
a. x and y+5 are both E, making y O
b. x-E, y+5=O, making y-E
c. x-O, y+5=E, making y O
x can be as O as E – INSUFFICIENT

(2)
6y^2+4y+25 = E
Means that 6y^2+4y = O
factorizing y we get y(6y+4) = O
6y+4 is obviously E, this means that y is O
But nothing about x….– INSUFFICIENT


(1) and (2)
From (2) we know that y is Even.
From (1) we know that to make x(y+5) even x can be as E (from a.) as O (from c.)
So, INSUFFICIENT

Answer is E.
Here E doesn’t mean Even

Thanks man.

ajmoney09 wrote:

4meonly wrote:About the 1st question:
From the table is can deduce that to make 130 cents we should by only 1 combination - 2*23 cents+4*21cents=130 cents.
Because from the main statement we know that we have nly 6 pencils.

Thats why (2) in SUFFicient making B the right answer

About 2nd question - no idea, too

But it does not say we have 6 pencils in the stem, it just says she bought some pencils we do not know she bough 6 pencils until statement 1.

Oh, yes, sorry
In general ,to make the total price 130 cents we have only one combination


Anybody with 2nd question?

4meonly wrote:

ajmoney09 wrote:

4meonly wrote:About the 1st question:
From the table is can deduce that to make 130 cents we should by only 1 combination - 2*23 cents+4*21cents=130 cents.
Because from the main statement we know that we have nly 6 pencils.

Thats why (2) in SUFFicient making B the right answer

About 2nd question - no idea, too

But it does not say we have 6 pencils in the stem, it just says she bought some pencils we do not know she bough 6 pencils until statement 1.

Oh, yes, sorry
In general ,to make the total price 130 cents we have only one combination


Anybody with 2nd question?

For sure someone help with the second I was CONFUSED!

I am taking test on Friday....really nervous! :!:

First of all dont be nervous. Its just one question, you have 37 different questions to face on quant.

from the question stem we can conclude:

500 is closer to x i.e. 400-600

400 is closer to y i.e. 300-500

Statement I

x < 500

x is closer to 400-499

we dont know anything about y. Insufficient.

Statement II

y < 400

y is closer to 300-399

we dont know anything about x. Insufficient.

Combining I & II
x is closer to 400-499
y is closer to 300-399


x+y = 400+300 = 700 x+y is closer to 700

or

x+y = 499+399 = 900 approx. is closer to 900

or that matter any values of x and y will give a range closer to either 700,800 or 900

Therefore Insufficient.

Hence E is the answer.

Let me know if you still have any doubts.

Good Luck!!!