BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
Vote for Target Test Prep, Newsweek Readers’ Choice Awards 2026
NEWSWEEK READERS’ CHOICE 2026

BIG NEWS! Target Test Prep has been nominated, and they’d love your vote!

TTP has worked incredibly hard to build the best test prep experience possible, and winning Newsweek’s 2026 Readers’ Choice Award for Best Test Prep would mean a lot to them. If TTP has helped you, they’d be incredibly grateful for your vote. You can vote once each day through September 9.

Vote for TTP
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

213 less or more

Expert replies
Source: — Data Sufficiency |

by money9111 » Sat Oct 17, 2009 9:34 pm
i think the answer is B.

choices A&D can be ruled out because the first statement doesn't tell you anything about the value of N which is essentially what you need to compare the answer too.

So you're left with BCE. B must be sufficient because when you substitute 10 for N you see that you have 1/10 - (1/(10+k)). So no matter what that denominator comes out to be... you're still subtracting something from the 1/10 which will result in a number less than 1/10.

I hope that's correct
Join the discussion

by Talkativetree » Sun Oct 18, 2009 6:21 pm
Is (1/n) - (1/(n + k)) <1/10?

1. K> 10
2. N> 10

Answer is C imo.

(1) insufficient because no idea what N is.
(2) insufficient alone because k can be negative. if k=-12, N=11, then

1/11 - 1/(11-12)< 1/10
1/11-(1/(-1)< 1/10
1/11-(-1)< 1/10
1/11+1 < 1/10
12/11 is not < 1/10

TOGETHER, we know that

1/(>10) - 1/[(>10)+(>10)] < 1/10

which at bare minimum (K=N=10.000001, which rounds to 10) means basically

1/10 - 1/20 < 1/10

1/20 < 2/20
Join the discussion

by gmat620 » Mon Oct 19, 2009 12:01 pm
(1/n) - (1/(n + k)) <1/10

(n + k - n)/((n + k)n) < 1/10

10k < n(n + k) ?

This is what its asking now

i> says K > 10

thus,
100 < n (n + k) ?
if n > 16...this is wrong, however, if n< = 16, this is true

so we can't say anything...Not sufficient

ii> says n > 10

10k < 10 ( 10 + k)
k < 10+ k ??

ohh yes we can say for sure that its always true..So sufficient

Answer should be B...


Please provide OA...thanks
Join the discussion

by Talkativetree » Mon Oct 19, 2009 6:13 pm
you mistake is that you're multiplying and dividing by variables that may or may not be negatives when you're in an inequality problem.

lets say we have
(n + k - n)/((n + k)n) < 1/10
k/[n(n+k)] < 1/10

look at my solution

2. N> 10

if n=100, but k = -101, then

k/[n(n+k)] < 1/10

-101/[100(100-101)} < 1/10
-101/-100 < 1/10

basically 1 < 1/10, which is false
Join the discussion

Re: 213 less or more

by fruti_yum » Thu Oct 22, 2009 4:20 pm
ern5231 wrote:Is (1/n) - (1/(n + k)) <1/10?

1. K> 10
2. N> 10
I think the answer is C

we arrive at equation k/n(n+k) < 0.1
therefore we need both values of n and k to arrive at a definite answer..

if k is 11.. and n = 11.. we ge the vlaue of 0.04 which is less than 0.1..

any value higher than 11 for either of the two variables will give a value less than 0.04.. therefore, less than 0.1

We can say definitively that value is less than 0.1

hence C
Join the discussion