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21 set 3

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by radhika1306 » Thu Aug 30, 2007 8:46 am
At a certain food stand, the price of each apple is $0.4 and the price of each orange is $0.6. Mary selects a total of 10 apples and oranges from the food stand, and the average (arithmetic mean) price of the 10 pieces of fruit is $0.56. How many oranges must Mary put back so that the average price of the pieces of fruit that she keeps is $0.52?
(A) 1
(B) 2
(C) 3
(D) 4
(E) 5
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Re: 21 set 3

by gabriel » Thu Aug 30, 2007 9:57 am
radhika1306 wrote:At a certain food stand, the price of each apple is $0.4 and the price of each orange is $0.6. Mary selects a total of 10 apples and oranges from the food stand, and the average (arithmetic mean) price of the 10 pieces of fruit is $0.56. How many oranges must Mary put back so that the average price of the pieces of fruit that she keeps is $0.52?
(A) 1
(B) 2
(C) 3
(D) 4
(E) 5
let the number of oranges be "x" .. then the number of apples = 10-x ..

So, we have (0.6*x+0.4(10-x))/10= 0.56 .. solve this for x and we get that there are 8 oranges and 2 apples ..

.. now remove "a" number of oranges to make the avg 0.52 ..

so, we have (0.6(8-a)+0.4*2)/(10-a) = 0.52 ..solve for a .. and u get a = 5 .. so the answer is E ..
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by radhika1306 » Thu Aug 30, 2007 10:05 am
Thank you
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