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-2<x<4

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Re: -2<x<4

by dtweah » Sat May 16, 2009 1:55 pm
shibal wrote:-2<x<4?

a.|x-2|<4
b.|x-1|<3
c.|x+1|<3
d.|x+2|<4
e. none of the above

OA:d
Approach from Answer choices and use definition

a. -2<x-2<4 add 2 to both sides to get x in middle
0 < No.
b. -3 < x-1<3. Add 1
-2 < x<4 Yes. . Correct answer is B.

d. -4 < x+2<4. Add -2
-6<x<-2. No. OA wrong.
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by artistocrat » Sat May 16, 2009 2:47 pm
Thats right, the correct answer is B. OA is incorrect.
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by shibal » Sun May 17, 2009 10:58 am
hummm. I just checked it and OA is D...
I still don't get it, how do u got B? could please explain with more details?
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by maihuna » Sun May 17, 2009 11:03 am
such Q requires dividing the two sides equally and substracting the half of that from x
4-(-2) = 6
6/2 = 3

so each side requires 3: -2-1<x-1<4-1 or -3<x-1<3 or |x-1|<3
Charged up again to beat the beast :)
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by shibal » Mon May 18, 2009 6:16 pm
maihuna wrote:such Q requires dividing the two sides equally and substracting the half of that from x
4-(-2) = 6
6/2 = 3

so each side requires 3: -2-1<x-1<4-1 or -3<x-1<3 or |x-1|<3
what do you mean by dividing them equally? average????
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by maihuna » Wed May 20, 2009 7:35 am
shibal wrote:
maihuna wrote:such Q requires dividing the two sides equally and substracting the half of that from x
4-(-2) = 6
6/2 = 3

so each side requires 3: -2-1<x-1<4-1 or -3<x-1<3 or |x-1|<3
what do you mean by dividing them equally? average????
The numerical values on either side of the modulus needs to be same, albeit with opposite sign, i.e -3<x<3, so fins the range of those number and divide them by 2 to get the equal no, and then suitably substract it from the mod vsar...hope it clarifies...
Charged up again to beat the beast :)
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by ousek » Wed May 20, 2009 7:54 am
Personnaly, with another method, I got also B.

Although : -2<x<4
answer d states that |x+2|<4

If you take x=3,99, the |x+2| is over 4 !
Answer D can not be the correct answer.
Fucking GMAT
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