Live GMAT classes with Target Test Prep start Nov 21 and Nov 22. First class free.

See classes
Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

Newsweek Readers’ Choice Awards 2026 winner: Target Test Prep, #1 Test Prep

Target Test Prep was voted #1 Best Test Prep in the 2026 Newsweek Readers’ Choice™ Awards.

★★★★★5.0563 reviews
GMATLiveTeachStarts Nov 22
Josh Braslow, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Josh Braslow, 20+ years in test prep

Nov 22 · Josh Braslow
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemandStart anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

EXECUTIVE ASSESSMENT

with

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemandStart anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

2 GMAT Prep Questions

Expert replies
by MonicaKhan » Sun Apr 22, 2007 3:31 pm
If anyone knows how to do either of the questions below, please let me know - thanks!

The temperature of a certain cub of coffee 10 minutes after it was poured was 120 degrees Fahrenheit. If the temperature F of the coffee t minutes after it was poured can be determined by the formula F = 120(2^-at) + 60, where F is in degrees Fahrenheit and is a constant, then the temperatre of the coffee 30 minutes after it was poured was how many degrees Fahrenheit?

(A) 65
(B) 75 (this is the answer)
(C) 80
(D) 85
(E) 90

The total of Company C's assets in 1994 was 300 percent greater than the total in 1993, which in turn was 400 percent greater than the total in 1992. If the total of Company C's assets in 1992 was N dollars, which of the following represents tht toal of Company C's assets, in dollars, in 1994?

A) 7N
B) 8N
C) 9N
D) 12N
E) 20N (this is the answer)

The answer is E, but I think it should be D.
Join the discussion
Source: — Problem Solving |

Re: 2 GMAT Prep Questions

by jayhawk2001 » Sun Apr 22, 2007 5:22 pm
MonicaKhan wrote:If anyone knows how to do either of the questions below, please let me know - thanks!

The temperature of a certain cub of coffee 10 minutes after it was poured was 120 degrees Fahrenheit. If the temperature F of the coffee t minutes after it was poured can be determined by the formula F = 120(2^-at) + 60, where F is in degrees Fahrenheit and is a constant, then the temperatre of the coffee 30 minutes after it was poured was how many degrees Fahrenheit?
First compute 'a' given the 10-min info
120 = 120 (2^(-10a)) + 60
2^-1 = 2^-10a
a = 1/10

Now, compute the 30 min info
F = 120(2^(-30/10)) + 60
= 120 * 2^-3 + 60
= 15 + 60
= 75
MonicaKhan wrote:
The total of Company C's assets in 1994 was 300 percent greater than the total in 1993, which in turn was 400 percent greater than the total in 1992. If the total of Company C's assets in 1992 was N dollars, which of the following represents tht toal of Company C's assets, in dollars, in 1994?

Lets call assets in 1993 as x and 1994 as y. We have to find y/N

x = 4N + N (x is 400% greater than N, so it is actually 5N)
x = 5N

Similarly --
y = 4x = 4*5*N = 20N
y/N = 20
Join the discussion

by Cybermusings » Sun Apr 22, 2007 11:22 pm
F = 120(2^-at) + 60 (f = temp of coffee "t" min after it was poured and "a" is a constant
Substituting 120 for F and 10 for t
120 = 120(2^-10a)+60
120-60 = 120(2^-10a)
60/120 = 2^-10a
1/2=2^-10a
1/2=1/2^10a
1=10a (equating the respective powers since the base is the same
Thus a =1/10

Now when t=30
F= 120[2^(-30*1/10)]+60
F=120(2^3)+60
F=120(2^-3)+60
=[120*(1/2^3)]+60
=(120/8 )+60
=75
Join the discussion

by Cybermusings » Sun Apr 22, 2007 11:25 pm
1992 = N
1993=N + 400N/100 = 5N
1994=5N + 300*5N/100 = 5N+15N=20N
Join the discussion