BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem
TTP OnDemand GMAT Video Course
Featured Course

Target Test Prep GMAT OnDemand

Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.

  • 715+ score guarantee — highest in the industry (99th percentile)
  • 52 chapters · 1,500+ lessons · 4,000+ practice questions
  • 400 hours of video · 1,500+ instructor-led HD smartboard lessons
  • 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
  • 24/7 live support + weekly Zoom office hours with GMAT instructors
  • TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
  • 1,200+ flashcards + AI-powered study assistant & daily calendar
  • OnDemand, LiveTeach & GMAT Bootcamp formats available
  • Also: GRE, SAT Math & Executive Assessment courses
  • MBA Admissions Consulting now available
  • 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
  • 200,000+ students served
  • 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★ 5.0 (559 reviews)
130-pt guarantee
$0 to start then $127/mo
Start Free 5-Day Trial Read 559 Reviews →

(2^5+2^6+2^7+2^8)^2=?

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
User avatar
Elite Legendary Member
Posts: 3991
Joined: Fri Jul 24, 2015 2:28 amFollowed by: 37 members
Location: Las Vegas, USA
Thanked: 19 times
by Max@Math Revolution » Thu May 10, 2018 6:45 am

Timer

00:00

Answers

A

B

C

D

E

Stats

Difficulty—

[GMAT math practice question]

$$\left(2^5+2^6+2^7+2^8\right)^2=?$$

$$A.\ 2^83^25^2$$
$$B.\ 2^{10}3^45^4$$
$$C.\ 2^{10}+2^{12}+2^{14}+2^{16}$$
$$D.\ 2^{25}+2^{36}+2^{49}+2^{64}$$
$$D.\ 2^{10}3^25^2$$
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |
User avatar
GMAT Instructor
Posts: 15539
Joined: Tue May 25, 2010 12:04 pmFollowed by: 1906 members
Location: New York, NY
Thanked: 13060 times
GMAT Score:790

by GMATGuruNY » Thu May 10, 2018 8:03 am
Max@Math Revolution wrote:[GMAT math practice question]

$$\left(2^5+2^6+2^7+2^8\right)^2=?$$

$$A.\ 2^83^25^2$$
$$B.\ 2^{10}3^45^4$$
$$C.\ 2^{10}+2^{12}+2^{14}+2^{16}$$
$$D.\ 2^{25}+2^{36}+2^{49}+2^{64}$$
$$D.\ 2^{10}3^25^2$$
(2� + 2� + 2� + 2�)²

= [2�(1 + 2 + 2² + 2³)]²

= [2�(15)]²

= (2� * 3 * 5)²

= 2¹�3²5².

The correct answer is E.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Elite Legendary Member
Posts: 3991
Joined: Fri Jul 24, 2015 2:28 amFollowed by: 37 members
Location: Las Vegas, USA
Thanked: 19 times

by Max@Math Revolution » Sun May 13, 2018 5:34 pm
=>



Therefore, E is the answer.
Answer : E
$$\left(2^5+2^6+2^7+2^8\right)^2$$
$$=\left(2^5\left(2^0+2^1+2^2+2^3\right)\right)^2$$
$$=\left(2^5\left(1+2+4+8\right)\right)^2$$
$$=\left(2^5\left(15\right)\right)^2$$
$$=\left(2^5\left(3\cdot5\right)\right)^2$$
$$=2^{10}\cdot3^2\cdot5^2$$

Therefore, E is the answer.
Answer : E
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
GMAT Instructor
Posts: 1462
Joined: Thu Apr 09, 2015 9:34 amFollowed by: 22 members
Location: New York, NY
Thanked: 39 times

by Jeff@TargetTestPrep » Tue May 15, 2018 3:44 pm
Max@Math Revolution wrote:[GMAT math practice question]

$$\left(2^5+2^6+2^7+2^8\right)^2=?$$

$$A.\ 2^83^25^2$$
$$B.\ 2^{10}3^45^4$$
$$C.\ 2^{10}+2^{12}+2^{14}+2^{16}$$
$$D.\ 2^{25}+2^{36}+2^{49}+2^{64}$$
$$D.\ 2^{10}3^25^2$$
From the expression in parentheses, we factor the common 2^5 and then simplify:

[2^5(1 + 2^1 + 2^2 + 2^3)]^2

2^10(1 + 2 + 4 + 8)^2

2^10(15)^2

2^10 x 5^2 x 3^2

Answer: E

Jeffrey Miller
Head of GMAT Instruction
[email protected]

Image

See why Target Test Prep is rated 5 out of 5 stars on BEAT the GMAT. Read our reviews
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1