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\((2^2-1)(2^2+1)(2^4+1)(2^8+1)=\)

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\((2^2-1)(2^2+1)(2^4+1)(2^8+1)=\)

by M7MBA » Sun Oct 25, 2020 5:53 am

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A

B

C

D

E

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\((2^2-1)(2^2+1)(2^4+1)(2^8+1)=\)

A. \(2^{16}-1\)

B. \(2^{16}+1\)

C. \(2^{32}-1\)

D. \(2^{128}-1\)

E. \(2^{16}(2^{16}-1)\)

Answer: A

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