Equation of x axis is y=0ern5231 wrote:how many points of intersection does Y = (X-1) (X +1) (X-3) have with x axis?
so to find the points of intersection, we have to solve
y= (X-1) (X +1) (X-3) =0
=> (X-1) (X +1) (X-3) =0
x=1, x= -1 and x=3 are the solutions
so there are 3 such points where the curve intersects x axis
