212. Abcd is a four integer, ac + bc + ad + bd = 65, | a + bcd | =?
213 W / x = x / y = y / z, then w / z =?
213 W / x = x / y = y / z, then w / z =?
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sanjana wrote:213) IMO : X/Y
From the given system :
x^2=wy
y^2=xz
Hence,
x^2/y^2 = wy/xz
Reducing, W/Z= X/Y
Hey !ern5231 wrote:212. Abcd is a four integer, ac + bc + ad + bd = 65, | a + bcd | =?
213 W / x = x / y = y / z, then w / z =?
yeah its all same w^3/x^3 or x^3/y^3 or y^3/z^3ern5231 wrote:OA w^3/x^3
We need more information to answer this question (or at least some clarification).ern5231 wrote:212. Abcd is a four integer, ac + bc + ad + bd = 65, | a + bcd | =?

xcusemeplz2009 wrote:yeah its all same w^3/x^3 or x^3/y^3 or y^3/z^3ern5231 wrote:OA w^3/x^3
When a/b = c/d,mehravikas wrote:Can you explain how is it same? I am confused.
xcusemeplz2009 wrote:yeah its all same w^3/x^3 or x^3/y^3 or y^3/z^3ern5231 wrote:OA w^3/x^3
nithi_mystics wrote:When a/b = c/d,mehravikas wrote:Can you explain how is it same? I am confused.
xcusemeplz2009 wrote:yeah its all same w^3/x^3 or x^3/y^3 or y^3/z^3ern5231 wrote:OA w^3/x^3
(a/b)^n = (c/d)^n
For example,
take a=4, b=2, c=6 and d=3
4/2 = 6/3 and you can substitute any value for n to check if 4^n/2^n = 6^n/3^n
2^n is always equal to 2^n