Is a^2-ab<0?
1) b<0
2)ab<0
The OA given is E but I feel it should be B.
It is given that ab<0. Hence a^2-(-ve)=>a^2+... which is positive. Hence >0 and should be sufficient. What is you opinion?
1) b<0
2)ab<0
The OA given is E but I feel it should be B.
It is given that ab<0. Hence a^2-(-ve)=>a^2+... which is positive. Hence >0 and should be sufficient. What is you opinion?
