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138 recurring decimal?

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Source: — Data Sufficiency |
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by xcusemeplz2009 » Tue Oct 06, 2009 8:00 pm
IMO A
It does not matter how many times you get knocked down , but how many times you get up
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by crackgmat007 » Tue Oct 06, 2009 9:38 pm
C for me.

(1) p=3^m -> gives the value of P only. What if q = 3^-m

(2) q=5^n -> gives the value of Q only.

1 & 2 - sufficient
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by meticulousboy » Thu Oct 08, 2009 7:00 am
crackgmat007 wrote:C for me.

(1) p=3^m -> gives the value of P only. What if q = 3^-m

(2) q=5^n -> gives the value of Q only.

1 & 2 - sufficient
For me its E.

I can tell you by looking at the problem that its not A or B or D!

Now, what happens when m=n=0? Or m=n= -1 ... Non-recurring.

If m=n=1 ...1/15 which is recurring (0.060606...)
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by mehravikas » Thu Oct 08, 2009 8:35 pm
It should be 'E' as we don't know the value of m and n. m and n could be zero or greater than zero.
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by crackgmat007 » Fri Oct 09, 2009 7:26 am
Oh yeah...missed picking numbers for m & n...should be E
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Re: 138 recurring decimal?

by Brent@GMATPrepNow » Sat Oct 10, 2009 8:03 pm
ern5231 wrote:X=1/pq. Does the value of X contain an infinite recurring decimal?
(1) p=3^m
(2) q=5^n
(1)&(2) combined
Case a: m=n=0 --> x is not infinite recurring decimal
Case b: m=n=1 --> x is infinite recurring decimal
Answer = E
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