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Each team will play with 11 other teams. Hence each team plays 11 games. Hence a total of 11*12 =132 games but since each game involves two teams divide 132/2 = 66fruti_yum wrote:If each of the 12 teams participating in a certain tournament plays exactly one game with each of the other teams, how many games will be played?
A. 144 B. 132 C. 66 D. 33 E. 23
OA is c
what's a method to tackle this problem?
This is a combinations problem where order does not matter. There are 12 teams, and only 2 teams selected to play one another.fruti_yum wrote:If each of the 12 teams participating in a certain tournament plays exactly one game with each of the other teams, how many games will be played?
A. 144 B. 132 C. 66 D. 33 E. 23
OA is c
what's a method to tackle this problem?
The number of games played is 12C2 = 12! / (2! x 10!) = (12 x 11) / 2 = 66.
