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12^(1/2) + 108^(1/2) + 48^(1/2) =

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by M7MBA » Mon Apr 15, 2019 1:55 am

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Answers

A

B

C

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Difficulty—

$$\sqrt{12}+\sqrt{108}+\sqrt{48}=$$
$$A.\ 12\sqrt{3}$$
$$B.\ 24$$
$$C.\ 12\sqrt{5}$$
$$D.\ 48\sqrt{3}$$
$$E.\ \sqrt{168}$$

[spoiler]OA=A[/spoiler]

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by GMATGuruNY » Mon Apr 15, 2019 2:37 am
M7MBA wrote:$$\sqrt{12}+\sqrt{108}+\sqrt{48}=$$
$$A.\ 12\sqrt{3}$$
$$B.\ 24$$
$$C.\ 12\sqrt{5}$$
$$D.\ 48\sqrt{3}$$
$$E.\ \sqrt{168}$$
√12 + (√9 * √12) + (√4 * √12)

= √12 + 3√12 + 2√12

= 6√12

= 6 * √4 * √ 3

= 12√3

The correct answer is A.
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by Scott@TargetTestPrep » Tue Apr 16, 2019 4:57 pm
M7MBA wrote:$$\sqrt{12}+\sqrt{108}+\sqrt{48}=$$
$$A.\ 12\sqrt{3}$$
$$B.\ 24$$
$$C.\ 12\sqrt{5}$$
$$D.\ 48\sqrt{3}$$
$$E.\ \sqrt{168}$$

[spoiler]OA=A[/spoiler]

Source: Veritas Prep
Simplifying, we have:

√4 x √3 + √36 x √3 + √16 x √3

2√3 + 6√3 + 4√3 = 12√3

Answer: A

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