Is the answer 10???
What i would do is...look at the numerator and denominator as (a^2-b^2)
In the numerator a-1001 and b-999
In the denominator a-101 and b-99
The formula for a^2-b^2 is (a+b)(a-b)
So(1001+999)(1001-999)/(101+99)(101-99)
=(2000)(2)/(200)(2)
2 gets cancelled in both numerator and denominator
2000/200=10
Hope ths helps
BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course
Redeem
Target Test Prep GMAT OnDemand
Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.
- 715+ score guarantee — highest in the industry (99th percentile)
- 52 chapters · 1,500+ lessons · 4,000+ practice questions
- 400 hours of video · 1,500+ instructor-led HD smartboard lessons
- 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
- 24/7 live support + weekly Zoom office hours with GMAT instructors
- TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
- 1,200+ flashcards + AI-powered study assistant & daily calendar
- OnDemand, LiveTeach & GMAT Bootcamp formats available
- Also: GRE, SAT Math & Executive Assessment courses
- MBA Admissions Consulting now available
- 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
- 200,000+ students served
- 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★
5.0
(559 reviews)
130-pt guarantee
$0 to start
then $127/mo
(1001^2-999^2)/(101^2-99^2)=
Source: Beat The GMAT — Problem Solving |
Can someone tell me how I can figure out how to solve these problems in general? I saw something like this on my actual GMAT and I was just perplexed as to how to even go about solving it.
x^2-y^2 = (x+y)*(x-y)imane81 wrote:Please help addressing this one...
(1001^2-999^2)/(101^2-99^2)=
A. 10
B. 20
C. 40
D. 80
E. 100
(1001^2-999^2)= (1001+999)(1001-999) = 2000*2
(101^2-99^2) =(101+99)(101-99) = 200*2
(1001^2-999^2)/(101^2-99^2)= 2000*2/200*2 = 10
Always borrow money from a pessimist, he doesn't expect to be paid back.
1001^2-999^2=(1000+1)^2-(1000-1)^2=(1000+1+1000-1)(1000+1-1000+1)=2*2000imane81 wrote:Please help addressing this one...
(1001^2-999^2)/(101^2-99^2)=
A. 10
B. 20
C. 40
D. 80
E. 100
using a^2-b^2=(a-b)(a+b)
similarly deno minator=2*200
value=2000*2/2*200=10
IMO A..
This problem is of the form a^2 - b^2 = (a+b)(a-b)
(1001^2-999^2)/(101^2-99^2)= (1001 + 999) (1001-999)/(101+99)(101-99)
= (2000*2)/(200*2)
= 10
This problem is of the form a^2 - b^2 = (a+b)(a-b)
(1001^2-999^2)/(101^2-99^2)= (1001 + 999) (1001-999)/(101+99)(101-99)
= (2000*2)/(200*2)
= 10
Great work on this thread, everyone.
Just to call attention to what swapna and neelimareddym did - I taught this to one of my students the other night, and it reiterates a critical point on GMAT quant. I don't advocate a ton of memorization but you MUST memorize and recognize the Difference of Squares rule:
a^2 - b^2 = (a + b)(a - b)
There are problems, like this one, that you just can't solve efficiently without this rule. Recognizing and applying Difference of Squares can be crucial on quite a few GMAT problems, so if you're reading this I implore you to make a point of knowing this one and of looking for it. When you see anything in the form a^2 - b^2 there's a very high likelihood that Differe nce of Squares will come into play. And don't forget about something like 99^2 - 1. 1 is the same thing as 1^2, so remember that you can use Difference of Squares there, too.
By the time you take the test, whenever you see large numbers or squares with one subtracted for another it should be almost second-nature to check for the ability to use Difference of Squares. I've posted on here before that, to me, it's like an invisible ink decoder or one of those spy toys you get as a kid - it's an instant game-changer to take something incredibly inconvenient and put it in an easy-to-use form. Make sure you take advantage of it!
Just to call attention to what swapna and neelimareddym did - I taught this to one of my students the other night, and it reiterates a critical point on GMAT quant. I don't advocate a ton of memorization but you MUST memorize and recognize the Difference of Squares rule:
a^2 - b^2 = (a + b)(a - b)
There are problems, like this one, that you just can't solve efficiently without this rule. Recognizing and applying Difference of Squares can be crucial on quite a few GMAT problems, so if you're reading this I implore you to make a point of knowing this one and of looking for it. When you see anything in the form a^2 - b^2 there's a very high likelihood that Differe nce of Squares will come into play. And don't forget about something like 99^2 - 1. 1 is the same thing as 1^2, so remember that you can use Difference of Squares there, too.
By the time you take the test, whenever you see large numbers or squares with one subtracted for another it should be almost second-nature to check for the ability to use Difference of Squares. I've posted on here before that, to me, it's like an invisible ink decoder or one of those spy toys you get as a kid - it's an instant game-changer to take something incredibly inconvenient and put it in an easy-to-use form. Make sure you take advantage of it!
Brian Galvin
GMAT Instructor
Chief Academic Officer
Veritas Prep
Looking for GMAT practice questions? Try out the Veritas Prep Question Bank. Learn More.
GMAT Instructor
Chief Academic Officer
Veritas Prep
Looking for GMAT practice questions? Try out the Veritas Prep Question Bank. Learn More.












