BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

1000 PS section 24- Q-8

Expert replies
by ash_maverick » Mon Jun 01, 2009 3:54 am
The pages of a report are numbered consecutively from 1 to 10. If the sum of the page numbers up to and including page number x of the report is equal to one more than the sum of the page numbers following page number x, then x =?

(A) 4 (B) 5 (C) 6 (D) 7 (E) 8


Expalnation will be appreciated.ThnX
Join the discussion
Source: — Problem Solving |

x[(x+1)]/2 = (11-x)(x+10)/2 +1

=>(x^2+x)/2 =[ (11x+110-x^2-10x)/2 ] +1

=>x^2+x = x+108-x^2

=>2x^2-108=0

=>x^2= 54

=> x=sqrt 54

what mistake i am doing here???
Join the discussion

by pathaniaus » Mon Jun 01, 2009 4:18 am
ok i jus did lit like this:
1 2 3 4 5 6 7 8 9 10
I started at wat if x = 5? i could readily see that it couldnt equal to 5 because 6+7+8+9+10 is far more than 1 when subracted by 1+2+3+4+5
I went up to x =6, still it wasnt one more
I went up to x=7, 1+2+3+4+5+6+7 = 28 then 8+9+10=27. this is the answer. x =7
Join the discussion

by ash_maverick » Mon Jun 01, 2009 4:30 am
pathaniaus wrote:ok i jus did lit like this:
1 2 3 4 5 6 7 8 9 10
I started at wat if x = 5? i could readily see that it couldnt equal to 5 because 6+7+8+9+10 is far more than 1 when subracted by 1+2+3+4+5
I went up to x =6, still it wasnt one more
I went up to x=7, 1+2+3+4+5+6+7 = 28 then 8+9+10=27. this is the answer. x =7
thanks for the answer..

But is there a way we can make algebraic equation out of it?
Join the discussion

I got it

by vineetbatra » Mon Jun 01, 2009 4:36 pm
Well this can be solved using Arithmetic Progression

Formula for AP is n(a1+an)/2

n = numbers in a sequence

Given the question we can come up with the following equation

n(1+x)/2 = (10-n)((X+1) + 10)/2 +1

We can replace n with x because we have consecutive numbers. Once we solve this we will get the quadratic equation

X^2 +x -56 = 0, the answer is -8, 7. So x is 7

Hope it helps.

Vineet
Join the discussion

I got it

by vineetbatra » Mon Jun 01, 2009 4:36 pm
Well this can be solved using Arithmetic Progression

Formula for AP is n(a1+an)/2

n = numbers in a sequence

Given the question we can come up with the following equation

n(1+x)/2 = (10-n)((X+1) + 10)/2 +1

We can replace n with x because we have consecutive numbers. Once we solve this we will get the quadratic equation

X^2 +x -56 = 0, the answer is -8, 7. So x is 7

Hope it helps.

Vineet
Join the discussion

I got it

by vineetbatra » Mon Jun 01, 2009 4:37 pm
Well this can be solved using Arithmetic Progression

Formula for AP is n(a1+an)/2

n = numbers in a sequence

Given the question we can come up with the following equation

n(1+x)/2 = (10-n)((X+1) + 10)/2 +1

We can replace n with x because we have consecutive numbers. Once we solve this we will get the quadratic equation

X^2 +x -56 = 0, the answer is -8, 7. So x is 7

Hope it helps.

Vineet
Join the discussion

Apologies

by vineetbatra » Mon Jun 01, 2009 4:39 pm
Apologies for the same post 3 times, I had a problem with my browser.
Join the discussion