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Source: — Data Sufficiency |
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by cramya » Mon Nov 24, 2008 8:57 pm
Stmt II

z=5x

x=1 z=5

x+10/2>z

If x=2 then x+10/2<z

INSUFF

Stmt I

Take x any value for z to be closer to 10 z has to be always greater than x+10/2

SUFF

There could be other approaches but this is mine!!!

A)
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by logitech » Mon Nov 24, 2008 9:35 pm
0........x........[(10+x)/2]...........10

If Z sits in the middle it means that it is the average of 10 and X but since Z is closer to the 10 it means that Z is greater than the average of 10 and X - SUF
LGTCH
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by vittalgmat » Mon Nov 24, 2008 10:30 pm
Thanks cramya, logitech.
I have a question:
How much time did u take to complete it. Mine was around 3 mins :(

Any quick shortcuts??

thanks
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by EricLien9122 » Tue Nov 25, 2008 12:33 pm
I don't see how statement 1 is sufficient.

If z is 9 and x is 8, then we have...

9>(8+10)/2?
9>9?

no....


Did I miss something?
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by Stuart@KaplanGMAT » Tue Nov 25, 2008 12:53 pm
EricLien9122 wrote:I don't see how statement 1 is sufficient.

If z is 9 and x is 8, then we have...

9>(8+10)/2?
9>9?

no....


Did I miss something?
Except that if z is 9 and x is 8, then z is NOT closer to 10 than it is to x!

We're only allowed to use numbers that fit the statements provided. Your values of x=8 and z=9 violate statement (1), so they're invalid.

By definition, the average of two numbers is right in the middle of the two numbers on the number line. So, if z is closer to the big number than the small number, z will definitely be greater than the average.
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by EricLien9122 » Tue Nov 25, 2008 1:05 pm
Thanks Stuart!
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