Yves can paint a certain fence in 1/2 the time it takes

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Yves can paint a certain fence in 1/2 the time it takes Marcel to paint the same fence. If they work together, each at his own constant rate, how many hours will it take them to paint the fence?

1) Yves can paint the fence by himself in 3 hours.
2) Working together, each at his own constant rate, they can paint the fence in 1/3 the time it would take Marcel, working alone, to paint the fence.

The OA is A

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Source: — Data Sufficiency |

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by gmatter2012 » Sun Nov 10, 2019 3:08 am
swerve wrote:Yves can paint a certain fence in 1/2 the time it takes Marcel to paint the same fence. If they work together, each at his own constant rate, how many hours will it take them to paint the fence?

1) Yves can paint the fence by himself in 3 hours.
2) Working together, each at his own constant rate, they can paint the fence in 1/3 the time it would take Marcel, working alone, to paint the fence.

The OA is A

Source: GMAT Prep
1) Yves can paint the fence by himself in 3 hours. So Marcel can do so in 6 hrs . Now we can find the time taken 1/3 + 1/6 =1/T
SUFF.
2) let Marcel take x hrs then Yves will take x/2 hrs and together they will do it in 1/x + 2/x = 3/x
We can solve for x
SUFF.

Ans- D

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by GMATGuruNY » Sun Nov 10, 2019 3:54 am
swerve wrote:Yves can paint a certain fence in 1/2 the time it takes Marcel to paint the same fence. If they work together, each at his own constant rate, how many hours will it take them to paint the fence?

1) Yves can paint the fence by himself in 3 hours.
2) Working together, each at his own constant rate, they can paint the fence in 1/3 the time it would take Marcel, working alone, to paint the fence.
Time and rate have a RECIPROCAL RELATIONSHIP.
Since Yves' time is ½ Marcel's time, Y's rate is TWO TIMES Marcel's rate.

Statement 1: Yves can paint the fence by himself in 3 hours.
Case 1: Fence = 6 units.
Since Yves' time for the 6-unit fence = 3 hours, Yves' rate = w/t = 6/3 = 2 units per hour, implying that Marcel's rate = 1 unit per hour and that their combined rate = 2+1 = 3 units per hour.
Since their combined rate = 3 units per hour, the time for Yves and Marcel to paint the 6-unit fence = w/r = 6/3 = 2 hours.

Case 2: Fence = 12 units.
Since Yves' time for the 12-unit fence = 3 hours, Yves' rate = w/t =12/3 = 4 units per hour, implying that Marcel's rate = 2 units per hour and that their combined rate = 4+2 = 6 units per hour.
Since their combined rate = 6 units per hour, the time for Yves and Marcel to paint the 12-unit fence = w/r = 12/6 = 2 hours.

Since the time in each case is THE SAME -- 2 hours -- Statement 1 is SUFFICIENT.

Statement 2: Working together, each at his own constant rate, they can paint the fence in 1/3 the time it would take Marcel, working alone, to paint the fence.
Since the time for Yves and Marcel together is â…“ the time for Marcel alone, the combined rate for Yves and Marcel together is THREE TIMES the rate for Marcel alone.
The rates yielded in Case 1 satisfy this condition:
Yves' and Marcel together = 3 units per hour, Marcel alone = 1 unit per hour.
In Case 1, the time for Yves and Marcel together = 2 hours.
Test these rates for a fence larger than 3 units.

Case 3: Fence = 30 units
Since their combined rate = 3 units per hour, the time for Yves and Marcel to paint a 30-unit fence = w/r = 30/3 = 10 hours.

Since the time in each case is DIFFERENT -- 2 hours in Case 1 but 10 hours in Case 2 -- Statement 2 is INSUFFICIENT.

The correct answer is A.
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by deloitte247 » Fri Nov 15, 2019 12:10 am
Let the time taken for Marcel to paint then fence = m.
Let the time taken for Yves to paint the fence = y
y = 1/2 * m = m/2
So, how many hours will it take them to paint the fence?
Statement 1: Yves can paint the fence by himself in 3 hours.
y = m/2 and m/2 = 3 hours
Therefore, m = 3 * 2 = 6 hrs
If Yves can finish painting the whole fence in 3 hrs, then in 1 hour, he would have painted 1/3 of the fence.
If Marcel can finish painting the whole fence in 6 hrs, then in 1 hour, he would have painted 1/6 of the fence.
Combining the work done by both Yves and Marcel for 1 hour;
1/3 + 1/6 = (6+3)/18 = 9/18 = 1/2
The two of them will complete 1/2 of the fence in 1 hour, hence, it will take them 2 hours to complete the whole fence.
Therefore, statement 1 is SUFFICIENT.

Statement 2: Making together each at his own constant rate, they can paint the fence in 1/3 the time it would take Marcel, working alone, to paint the fence.
From the question stem, time taken for Marcel to paint the fence when working alone = m.
And from this statement, when working together, the time taken to paint the whole fence is 1/3 of m.
Marcel and Yves will finish painting the fence in 1/2 * m hour = m/3 hours
But the value of' is unknown, hence, statement 1 alone is SUFFICIENT.

Answer = option A