1. AB has to be parallel to x-axis...the range for x-axis for this question is -3 ≤ x ≤ 5..i.e 9 points.......therefore,
ways to choose 2 points out of 9..and order matters = 9 P 2 = 9! / 7 ! = 72
And each of the above permutation can happen in 10 ways ( consider y axis also)...So total ways for side AB = 72*10 = 720
2. As the right angle has to be at point A, the point C has to be directly above or directly below the point A, as the Y range is 2 ≤ y ≤11 i.e. 10 points...and A has already taken 1 point....C can take the remaining 9 points.
So Total no. of triangles that can be formed = 720 * 9 =
6480
GmatKiss wrote:A right triangle ABC has to be constructed in the xy-plane so that the right angle is at A and AB is parallel to x axis. The coordinates of A, B and C are to satisfy the inequalities -3 ≤ x ≤ 5 and 2 ≤ y ≤11 and x and y are integers. The number of different triangles that can be constructed with these properties are?
90
900
8100
6480
10000