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x/y?

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Master | Next Rank: 500 Posts
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x/y?

by grandh01 » Thu Aug 23, 2012 2:41 pm
If x (a + b) = y, where y ≠ 0 and 2a
= 3b = 1, then =
y/x
(A)1/6
(B)1/3
(C)2/3
(D)5/6
(E)6/5
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by truplayer256 » Thu Aug 23, 2012 5:16 pm
2a = 3b = 1 => a = 1/2 and b = 1/3

x(a + b) = y => y/x = (a + b) = 1/2 + 1/3 = 5/6

Choose D.
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by alex.gellatly » Thu Aug 23, 2012 7:43 pm
grandh01 wrote:If x (a + b) = y, where y ≠ 0 and 2a
= 3b = 1, then =
y/x
(A)1/6
(B)1/3
(C)2/3
(D)5/6
(E)6/5
2a=3b=1 means that 2a=1 and 3b=1. Solving for them individually we get a=1/2 and b=1/3
If x(a+b)=y; then a+b=y/x since the question is asking for y/x, then simply plug the values we got for a and b into the equation:

1/2 + 1/3 = y/x
5/6= y/x
The correct answer is D
A useful website I found that has every quant OG video explanation:

https://www.beatthegmat.com/useful-websi ... tml#475231
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