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rabbit rate

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Source: — Data Sufficiency |
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by anshumishra » Sat Dec 18, 2010 11:39 am
prachich1987 wrote:Plz help in solving the attached.thanks!
Your attachment only shows the 1st statement. Do you need help with only that part or do you want to upload the full question?

Thanks
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by Rahul@gurome » Sat Dec 18, 2010 11:56 am
Is the statement sufficient?

A group of rabbits multiplies at a constant rate. By what factor does its population increase every day?

(1) The population grows from 200 to 5,000 in one week.
Say everyday the population increases by a factor x.
Initial population = 200
Population at the end of 1st day = 200*x
Population at the end of 2nd day = 200*(x^2)
Population at the end of 3rd day = 200*(x^3)
...
Population at the end of 7th day = 200*(x^7)

Now, 200*(x^7) = 5000 => (x^7) = 5000/200 = 25 => x = 7-th root of 25

Therefore the statement is sufficient.
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by anshumishra » Sat Dec 18, 2010 12:21 pm
It is a geometric progression use case :

a = 200
n = 7

5000 = 200*r^7 --- An equation with one variable , we can find r ( = 25 ^1/7) -- Sufficient.
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by prachich1987 » Sat Dec 18, 2010 8:41 pm
Thanks Rahul
Thanks mishraanshu,I wanted to upload only that part
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