How to solve this algebrically?
What is the value of |x| ?
(1) x = -|x|
(2) x^2 = 4
OA B
Whats wrong with this method ?
) x = -|x|
this x = - (-x) or x = - (+x)
since |x| can be +ve pr -ve
thus
x = x or x = -x
x - x = 0 or x + x = 0
0=0 or 2x = 0
x =0....
st 2 says x = +/- 2
but |x| is always +ve so x = 2
thus it is D
but OA is B
What is the value of |x| ?
(1) x = -|x|
(2) x^2 = 4
OA B
Whats wrong with this method ?
) x = -|x|
this x = - (-x) or x = - (+x)
since |x| can be +ve pr -ve
thus
x = x or x = -x
x - x = 0 or x + x = 0
0=0 or 2x = 0
x =0....
st 2 says x = +/- 2
but |x| is always +ve so x = 2
thus it is D
but OA is B

















