x^6 - y^6 = (x^3 - y^3?) (x^3 + y^3) = 0teekayy wrote:If x^6 - y^6 = 0, what is the value of x^3 - y^3?
(1) x is positive
(2) y is greater than 1
answer: C
Either x^3 - y^3 = 0 , which means X=Y
x^3 + y^3 = 0, which means X = -Y
(1) x is positive - Insuf, we don't know anything about Y
(2) y is greater than 1 -Insuf we dont know anything about X
1+2) x and y positive
so x^3 - y^3 = 0
C

















