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Absolute Values

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Source: — Data Sufficiency |

by pemdas » Fri Dec 30, 2011 7:33 am
st(1) implies |p|>q Insuff
st(2) p>q Isuff
combined st(1&2): still Insuff

e



LeoBen wrote:Is P > |Q|

a. P^2 > Q^3
b. P > Q

[spoiler]OA: E[/spoiler]



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by neelgandham » Fri Dec 30, 2011 6:09 pm
Is P > |Q|
a. P^2 > Q^3
If P = 1 and Q = -3
P^2 > Q^3 (1 > -27) and P < |Q|

If P = 4 and Q = -3
P^2 > Q^3 (16 > -27) and P > |Q|.
We get two different answers(Yes and NO). Hence Insufficient.
b. P > Q
If P = 1 and Q = -3
P > Q (1 > -3) and P < |Q|

If P = 4 and Q = -3
P > Q (4 > -3) and P > |Q|
We get two different answers(Yes and NO). Hence Insufficient.
Using statements 1 and 2
If P = 1 and Q = -3
P > Q (1 > -3),P^2 > Q^3 (1 > -27) and P < |Q|

If P = 4 and Q = -3
P > Q (4 > -3),P^2 > Q^3 (16 > -27) and P > |Q|

We get two different answers(Yes and NO). Hence Insufficient. Answer E
Anil Gandham
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by LeoBen » Sat Dec 31, 2011 5:23 am
neelgandham wrote:Is P > |Q|
a. P^2 > Q^3
If P = 1 and Q = -3
P^2 > Q^3 (1 > -27) and P < |Q|

If P = 4 and Q = -3
P^2 > Q^3 (16 > -27) and P > |Q|.
We get two different answers(Yes and NO). Hence Insufficient.

Thanks -- when p is 4 & q is -3 => absolute of q > p, isnt it?
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