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OG12 PS #148

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OG12 PS #148

by jscpba » Sun Feb 06, 2011 9:20 am
What is the quickest way to solve this?

If x, y, and k are positive numbers such that (x/x+y)(10) + (y/x+y)(20)= k and if x is less than y, which of the following could be the value of k?

a. 10
b. 12
c. 15
d. 18
e. 30
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by maihuna » Sun Feb 06, 2011 9:59 am
it ca nbe viewed as weighted avg of 10 and 20, we knew the weighted avg will be close to 20 since x and y are positive no, and x < y, its kind of x/x+y will be less than y/x+y, so any answer more than 15 and less than 20 will satisfy. 18 is there.
Charged up again to beat the beast :)
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