vaibhav101 wrote:2 workers A and B working together completed a job in 5 days. If A worked twice as efficiently as he actually did and B worked 1/3rd as efficiently as he actually did, the work would have been completed in 3 days. A alone could complete the work in:
A 21/4 days
B 25/4 days
C 15/2 days
D 75/8 days
E none of these
Let the job = 15 units.
Since A and B take 5 days to produce the 15-unit job, A+B = w/t = 15/5 = 3 units per day.
Thus:
A+B = 3.
Since 2A and (1/3)B take 3 days to produce the 15-unit job, 2A + (1/3)B = w/t = 15/3 = 5 units per day.
Thus:
2A + (1/3)B = 5
6A + B = 15.
Subtracting the red equation from the blue equation, we get:
(6A + B) - (A+B) = 15 - 3
5A = 12
A = 12/5 units per day.
Since A's rate = 12/5 units per day, the time for A alone to produce the 15-unit job = 15/(12/5) = 75/12 = 25/4 days.
The correct answer is
B.
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