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Expert replies
by rintoo22 » Thu Mar 21, 2013 8:43 am
In the question (Attached). I did solve and manage to get an answer E (thursday). However the real answer is C (Tuesday).

The solution is as follows
June 25 1982 : Friday
June 25 1983 : Saturday
June 25 1984 (Leap Year) : Monday
June 25 1985 : Tuesday
June 26 1986 : Wedensday
June 26 1987 : Thursday. (This should be the answer).

Kindly throw some light.
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Source: — Problem Solving |

by hemant_rajput » Thu Mar 21, 2013 9:53 am
rintoo22 wrote:In the question (Attached). I did solve and manage to get an answer E (thursday). However the real answer is C (Tuesday).

The solution is as follows
June 25 1982 : Friday
June 25 1983 : Saturday
June 25 1984 (Leap Year) : Monday
June 25 1985 : Tuesday
June 26 1986 : Wedensday
June 26 1987 : Thursday. (This should be the answer).

Kindly throw some light.
Your approach and answer both are correct. There must be some mistake in the OA.
I'm no expert, just trying to work on my skills. If I've made any mistakes please bear with me.
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by killerdrummer » Thu Mar 21, 2013 9:56 am
What is source ?

btw you are right it should be Thursday!!
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by GMATGuruNY » Thu Mar 21, 2013 10:04 am
June 25 1982, fell on a Friday. On which day of the week did June 25, 1987 fall. (Note : 1984 was a leap year).

a) Sunday
b) Monday
c) Tuesday
d) Wednesday
e) Thursday
Between 1982 and 1987 are 4 non-leap years and 1 leap year.
Each non-leap year is composed of 365 days; a leap year is composed of 366 days.
Thus, from June 25, 1982 to June 25, 1987, the total number of days = 4(365) + 366.

Since June 25, 1982 is a Friday, every passing of 7 days will yield another Friday.
364 is a multiple of 7.
Rephrase the total number of days in terms of 364:
4(365) + 366

= 4(364+1) + (364+2)

= (4*364 + 4) + (364+2)

= 5(364) + 6

= (multiple of 7) + 6

= Friday + 6 days

= Thursday.

The correct answer is E.
If the OA is C, then the OA is incorrect.
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