BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

combination

This topic has expert replies
Post new topic Post Reply
Previous Topic Next Topic
Junior | Next Rank: 30 Posts
Posts: 20
Joined: Tue Nov 10, 2009 9:06 am

combination

by budetta4 » Wed Feb 17, 2010 2:59 am
if 3 boys and three girls must sit in a row of six chair but neither boys or girls are allowe to sit, how many different seating arrangemets can be made?

A 12
B 36
C72
D 180
E 360

could spmeone explain me how to solve it?
Top
Source: — Problem Solving |
Senior | Next Rank: 100 Posts
Posts: 81
Joined: Wed Apr 08, 2009 3:12 pm
Location: South Korea
Thanked: 4 times

by sadullaevd » Wed Feb 17, 2010 3:04 am
could you plz check question stem,

i cant understand it, guess others will also find it unclear.

thank you.
Stay skeptical,
Think critically,
Assume nothing.
Top
User avatar
Community Manager
Posts: 1537
Joined: Mon Aug 10, 2009 6:10 pm
Thanked: 653 times
Followed by:252 members

by papgust » Wed Feb 17, 2010 3:05 am
Can you check the question? It doesn't sound logical. First, it says that boys and girls must in a row, but then it says that neither boys nor girls are allowed to sit.
Top
User avatar
Legendary Member
Posts: 1560
Joined: Tue Nov 17, 2009 2:38 am
Thanked: 137 times
Followed by:5 members

by thephoenix » Wed Feb 17, 2010 3:13 am
budetta4 wrote:if 3 boys and three girls must sit in a row of six chair but neither boys nor girls are allowed to sit together, how many different seating arrangemets can be made?

A 12
B 36
C72
D 180
E 360

could spmeone explain me how to solve it?
i guess the question is like the abve one

if yes than IMO B sud be the ans

3 boys can be placed in 3!=6 ways
in b/n three places 3 girls can seated in 3!=6 ways
tot=6*6=36
Top
User avatar
Legendary Member
Posts: 1275
Joined: Thu Sep 21, 2006 11:13 pm
Location: Arabian Sea
Thanked: 125 times
Followed by:2 members

by ajith » Wed Feb 17, 2010 3:31 am
budetta4 wrote:if 3 boys and three girls must sit in a row of six chair but neither boys or girls are allowed to sit together, how many different seating arrangements can be made?

A 12
B 36
C72
D 180
E 360

could someone explain me how to solve it?
_ _ _ _ _

We can either arrange boys in 1st , 3rd and 5th slot , or 2nd, 4th and 6th slot
Boys can be arranged within themselves in 6 ways
Girls can be arranged within themselves in 6 ways

Total no of ways = 2*6*6 = 72

C
Always borrow money from a pessimist, he doesn't expect to be paid back.
Top
Post new topic Post Reply
• Page 1 of 1