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word problem

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by vladmire » Wed Oct 15, 2008 6:59 pm
in may, xiang sold 15 used cars. for these 15 cars the range of the selling prices was 15000 and the lowest selling price was 4500. in june xiang sold 10 used cars. for these 10 cars, the range of the selling prices was 16500 and the lowest selling price was 6100. what was the range of the selling prices of the 25 used cars sold by xiang in May and June?

a)15,600
b)15,750
c)16,820
d)18,100
e)19,200
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Re: word problem

by Gmatss » Wed Oct 15, 2008 7:57 pm
vladmire wrote:in may, xiang sold 15 used cars. for these 15 cars the range of the selling prices was 15000 and the lowest selling price was 4500. in june xiang sold 10 used cars. for these 10 cars, the range of the selling prices was 16500 and the lowest selling price was 6100. what was the range of the selling prices of the 25 used cars sold by xiang in May and June?

a)15,600
b)15,750
c)16,820
d)18,100
e)19,200
should be d
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by rohangupta83 » Thu Oct 16, 2008 12:32 am
Range in May

4500 to 19500

Range in June

6100 to 22600

Net Range for the 2 months (or 25 cars sold in this period)

22600 - 4500 = 18100
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by lunarpower » Thu Oct 16, 2008 2:23 am
rohangupta83 wrote:Range in May

4500 to 19500

Range in June

6100 to 22600

Net Range for the 2 months (or 25 cars sold in this period)

22600 - 4500 = 18100
pretty solid, yes.

just make sure that you know: RANGE = maximum - minimum. just like any other elementary equation involving 3 quantities, this one will yield the 3rd quantity if you know two of them. since this problem gives you the range and the minimum for each of the two months, you can just plug in to find the maximum for each month.
Ron has been teaching various standardized tests for 20 years.

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by raunekk » Thu Oct 16, 2008 2:57 am
D for sure!!
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by somail » Sun Nov 09, 2008 1:36 pm
rohangupta83 wrote:Range in May

4500 to 19500

Range in June

6100 to 22600

Net Range for the 2 months (or 25 cars sold in this period)

22600 - 4500 = 18100

Can someone explain this further. I can't get the reasoning behind this.

The Max these values are $16,500 and $15,000. Why are you adding the cheapest car of 4,500 and 6,100.

Range is max - min. The max sale value for $16,500 and min was $4,500. So isn't the range $12,000
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by iamcste » Sun Nov 09, 2008 1:56 pm
somail wrote:
rohangupta83 wrote:Range in May

4500 to 19500

Range in June

6100 to 22600

Net Range for the 2 months (or 25 cars sold in this period)

22600 - 4500 = 18100

Can someone explain this further. I can't get the reasoning behind this.

The Max these values are $16,500 and $15,000. Why are you adding the cheapest car of 4,500 and 6,100.

Range is max - min. The max sale value for $16,500 and min was $4,500. So isn't the range $12,000



Max/highest is not 16500..Its the range is 16500...i.e means highesst-lowest=16500..

you know the lowest so you get the highest
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by vishubn » Sun Nov 09, 2008 4:51 pm
first 15 cars !

H-L=15000
H=15000+4500
H=19500

remaining 10 cars

H-L=16500
h=16500+6100
H=22600

so for all 25 cars

ranhe is =22600-4500
18100

Oa is D
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by lunarpower » Fri Nov 14, 2008 1:41 am
somail wrote:The Max these values are $16,500 and $15,000. Why are you adding the cheapest car of 4,500 and 6,100.
no.

you have to make sure that you read the question very, very carefully. the 16,500 and 15,000 are ranges, not maximum values.

since range = maximum - minimum, you can rearrange to produce maximum = minimum + range.
applying that particular equation is what produces the results arrived at by the various posters in this problem.
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