Mo2men wrote:Alice has $15, which is enough to buy 11 muffins and 7 brownies, is $45 enough to buy 27 muffins and 27 brownies?
(1) $15 is enough to buy 7 muffins and 11 brownies.
(2) $15 is enough to buy 10 muffins and 8 brownies.
Test EXTREMES.
Since $15 is enough to buy 11 muffins and 7 brownies, the greatest possible cost for 11 muffins and 7 brownies is $15:
11M + 7B = 15.
Statement 1:
Since $15 is enough to buy 7 muffins and 11 brownies, the greatest possible cost for 7 muffins and 11 brownies is $15:
7M + 11B = 15.
Adding together the two equations in blue, we get:
18M + 18B = 30.
Dividing by 6, we get:
3M + 3B = 5.
Multiplying by 9, we get:
27M + 27B = 45.
Implication:
The greatest possible cost for 27 muffins and 27 brownies is $45.
Thus, $45 is enough to buy 27 muffins and 27 brownies.
SUFFICIENT.
Statement 2:
Case 1: Minimize the cost for each muffin and brownie
Let the cost for each muffin = $0.01 and the cost for each brownie = $0.01.
In this case, $45 is clearly enough to buy 27 muffins and 27 brownies.
Case 2: Maximize the cost for each brownie, minimize the cost for each muffin
Since $15 is enough to buy 8 brownies -- and 15/8 = 1.875 -- it is possible that each brownie costs $1.80, while each muffin costs $0.01.
Cost for 27 muffins and 27 brownies:
(27)(0.01) + (27)(1.8) > 45.
In this case, $45 is NOT enough to buy 27 muffins and 27 brownies.
INSUFFICIENT.
The correct answer is
A.
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