BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem
TTP OnDemand GMAT Video Course
Featured Course

Target Test Prep GMAT OnDemand

Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.

  • 715+ score guarantee — highest in the industry (99th percentile)
  • 52 chapters · 1,500+ lessons · 4,000+ practice questions
  • 400 hours of video · 1,500+ instructor-led HD smartboard lessons
  • 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
  • 24/7 live support + weekly Zoom office hours with GMAT instructors
  • TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
  • 1,200+ flashcards + AI-powered study assistant & daily calendar
  • OnDemand, LiveTeach & GMAT Bootcamp formats available
  • Also: GRE, SAT Math & Executive Assessment courses
  • MBA Admissions Consulting now available
  • 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
  • 200,000+ students served
  • 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★ 5.0 (559 reviews)
130-pt guarantee
$0 to start then $127/mo
Start Free 5-Day Trial Read 559 Reviews →

probability

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Source: — Data Sufficiency |
Legendary Member
Posts: 1035
Joined: Wed Aug 27, 2008 10:56 pmFollowed by: 1 member
Thanked: 104 times

by scoobydooby » Thu Apr 16, 2009 9:35 pm
probability that event E or event F or both will occur=>probability atleast 1 of them will occur: p(EUF)=p(E)+p(F)-P(F and E)

1) gives only p(E). not. sufficient.

2) gives only p(F). not sufficient

together, we do not have P(F and E). so both together not sufficien

E
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Senior | Next Rank: 100 Posts
Posts: 55
Joined: Wed Mar 18, 2009 9:56 am
Thanked: 2 times

by apple100 » Thu Apr 16, 2009 9:39 pm
scoobydooby wrote:probability that event E or event F or both will occur=>probability atleast 1 of them will occur: p(EUF)=p(E)+p(F)-P(F and E)

1) gives only p(E). not. sufficient.

2) gives only p(F). not sufficient

together, we do not have P(F and E). so both together not sufficien

E
is P(F&E) not equal to P(E) * P(F)?
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 1035
Joined: Wed Aug 27, 2008 10:56 pmFollowed by: 1 member
Thanked: 104 times

by scoobydooby » Thu Apr 16, 2009 9:43 pm
P(F&E) = P(E) * P(F) only when E and F are independent events, ie the out come of one event is not dependent on the outcome of the other.

also, we do not know if E and F are mutually exclusive events, ie they cant occur together, so cant say P(F &E)=0
Last edited by scoobydooby on Thu Apr 16, 2009 9:49 pm, edited 1 time in total.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Senior | Next Rank: 100 Posts
Posts: 55
Joined: Wed Mar 18, 2009 9:56 am
Thanked: 2 times

by apple100 » Thu Apr 16, 2009 9:45 pm
scoobydooby wrote:P(F&E) = P(E) * P(F) only when E and F are independent events, ie the out come of one event is not dependent on the outcome of the other.
and in this case, we do not know whether the events are independent or not, correct?
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 1035
Joined: Wed Aug 27, 2008 10:56 pmFollowed by: 1 member
Thanked: 104 times

by scoobydooby » Thu Apr 16, 2009 9:50 pm
apple100 wrote:
scoobydooby wrote:P(F&E) = P(E) * P(F) only when E and F are independent events, ie the out come of one event is not dependent on the outcome of the other.
and in this case, we do not know whether the events are independent or not, correct?
yes, thats right. no information on the nature of the events.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1