BTGmoderatorDC wrote:A perfectly spherical satellite with a radius of 4 feet is being packed for shipment to its launch site. If the inside dimensions of the rectangular crates available for shipment, when measured in feet, are consecutive even integers, then what is the volume of the smallest available crate that can be used?
(Note: the volume of a sphere is given by the equation v=(4/3)pie r^3 .)

(A) 48
(B) 192
(C) 480
(D) 960
(E) 1,680

OA D

Source: Princeton Review

Given: Radius of the spherical satellite = 4ft, so diameter = 8 ft

The minimum dimension of the rectangular box (crate) must be 8*8*8 in order for the spherical satellite to perfectly fit into the crate.

Since the dimensions of the crate are consecutive even integers, the minimum values of the dimensions of the crates must be 8, 8 + 2 = 10 and 10 + 2 = 12

=> Volume of the rectangular box (Crate) = 8*10*12 = 960 ft^3

The correct answer: D

Hope this helps!

-Jay
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BTGmoderatorDC wrote:A perfectly spherical satellite with a radius of 4 feet is being packed for shipment to its launch site. If the inside dimensions of the rectangular crates available for shipment, when measured in feet, are consecutive even integers, then what is the volume of the smallest available crate that can be used?
(Note: the volume of a sphere is given by the equation v=(4/3)pie r^3 .)

(A) 48
(B) 192
(C) 480
(D) 960
(E) 1,680

The shortest dimension of the rectangular crate has to be at least the diameter of the spherical satellite; therefore, that dimension has to be at least 8. Since the dimensions of the crate are consecutive even integers, the smallest possible volume of the crate is:

8 x 10 x 12 = 960

Answer: D