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100 points for $49 worth of Veritas practice GMATs FREE VERITAS PRACTICE GMAT EXAMS Earn 10 Points Per Post Earn 10 Points Per Thanks Earn 10 Points Per Upvote ## A perfectly spherical satellite with a radius of 4 feet is ##### This topic has 2 expert replies and 1 member reply ### Top Member ## A perfectly spherical satellite with a radius of 4 feet is ## Timer 00:00 ## Your Answer A B C D E ## Global Stats Difficult A perfectly spherical satellite with a radius of 4 feet is being packed for shipment to its launch site. If the inside dimensions of the rectangular crates available for shipment, when measured in feet, are consecutive even integers, then what is the volume of the smallest available crate that can be used? (Note: the volume of a sphere is given by the equation v=(4/3)pie r^3 .) (A) 48 (B) 192 (C) 480 (D) 960 (E) 1,680 OA D Source: Princeton Review ### GMAT/MBA Expert GMAT Instructor Joined 22 Aug 2016 Posted: 1770 messages Followed by: 28 members Upvotes: 470 BTGmoderatorDC wrote: A perfectly spherical satellite with a radius of 4 feet is being packed for shipment to its launch site. If the inside dimensions of the rectangular crates available for shipment, when measured in feet, are consecutive even integers, then what is the volume of the smallest available crate that can be used? (Note: the volume of a sphere is given by the equation v=(4/3)pie r^3 .) (A) 48 (B) 192 (C) 480 (D) 960 (E) 1,680 OA D Source: Princeton Review Given: Radius of the spherical satellite = 4ft, so diameter = 8 ft The minimum dimension of the rectangular box (crate) must be 8*8*8 in order for the spherical satellite to perfectly fit into the crate. Since the dimensions of the crate are consecutive even integers, the minimum values of the dimensions of the crates must be 8, 8 + 2 = 10 and 10 + 2 = 12 => Volume of the rectangular box (Crate) = 8*10*12 = 960 ft^3 The correct answer: D Hope this helps! -Jay _________________ Manhattan Review GRE Prep Locations: GMAT Classes Chicago | GRE Prep Course San Diego | GRE Prep Atlanta | TOEFL Prep Classes Houston | and many more... Schedule your free consultation with an experienced GMAT Prep Advisor! Click here. ### Top Member Legendary Member Joined 29 Oct 2017 Posted: 783 messages Followed by: 4 members Since the radius is 4 feet, the smallest side should be equal to the diameter. Hence the shortest side will be 8 feet and therefore the rest of the sides will be 10 and 12 feet. Volume will be 8 x 10 x 12 = 960 ft^3. Regards! ### GMAT/MBA Expert GMAT Instructor Joined 25 Apr 2015 Posted: 2012 messages Followed by: 15 members Upvotes: 43 BTGmoderatorDC wrote: A perfectly spherical satellite with a radius of 4 feet is being packed for shipment to its launch site. If the inside dimensions of the rectangular crates available for shipment, when measured in feet, are consecutive even integers, then what is the volume of the smallest available crate that can be used? (Note: the volume of a sphere is given by the equation v=(4/3)pie r^3 .) (A) 48 (B) 192 (C) 480 (D) 960 (E) 1,680 The shortest dimension of the rectangular crate has to be at least the diameter of the spherical satellite; therefore, that dimension has to be at least 8. Since the dimensions of the crate are consecutive even integers, the smallest possible volume of the crate is: 8 x 10 x 12 = 960 Answer: D _________________ Scott Woodbury-Stewart Founder and CEO • Free Veritas GMAT Class Experience Lesson 1 Live Free Available with Beat the GMAT members only code • 5-Day Free Trial 5-day free, full-access trial TTP Quant Available with Beat the GMAT members only code • Free Practice Test & Review How would you score if you took the GMAT Available with Beat the GMAT members only code • Magoosh Study with Magoosh GMAT prep Available with Beat the GMAT members only code • Award-winning private GMAT tutoring Register now and save up to$200

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