Which of the following fractions has the greatest value?
A. 3/8!
B. 6(4!) / 5(9!)
C. 4(3!) / 9!
D. 3 / 5(7!)
E. 14 / 5(8!)
A. 3/8!
B. 6(4!) / 5(9!)
C. 4(3!) / 9!
D. 3 / 5(7!)
E. 14 / 5(8!)
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Let us try to make a common denominator equal to 10!, so that we can compare the terms by their numerators...gmatter2012 wrote:Which of the following fractions has the greatest value?
When comparing, do two things, compare the things with the same denominator, then convert everything to a common denominator and compare.gmatter2012 wrote:Which of the following fractions has the greatest value?
A. 3/8!
B. 6(4!) / 5(9!)
C. 4(3!) / 9!
D. 3 / 5(7!)
E. 14 / 5(8!)
Anurag@Gurome wrote: Let us try to make a common denominator equal to 10!, so that we can compare the terms by their numerators...Option D is the greatest.
- A. 3/8! = (3*9*10)/(8!*9*10) = (3*9*10)/10! = 270/10!
B. 6(4!)/5(9!) = (6*4!*2)/(9!2*5) = (6*24*2)/10! = 288/10!
C. 4(3!)/9! = (4*3!*10)/(9!*10) = (4*6*10)/10! = 240/10!
D. 3/5(7!) = (3*2*8*9)/(7!*8*9*5*2) = (3*2*8*9)/10! = 432/10!
E. 14/5(8!) = (14*2*9)/(8!*9*5*2) = (14*9*2)/10! = 252/10!
The correct answer is D.
eagleeye wrote:
When comparing, do two things, compare the things with the same denominator, then convert everything to a common denominator and compare.
Pairing in groups can save us valuable time.
First compare A and E. We have 14/5 vs 3, 3 wins. Eliminate E.
Then compare B and C. 6/5*4! Vs( 4*3 != 4!). B wins, eliminate C.
Compare A and D. To compare we need 8! In both at the denominator.
D is (3/5)*(1/7!) = (3*8/5)/8! = (24/5)/(8!)
Now comparing A and D. 3 vs 24/5, 24/5 wins. Eliminate A......