AndrewRivera7793 wrote:When the positive integer n is divided by 45, the remainder is 18. Which of the following must be a divisor of n?
A) 11
B) 9
C) 7
D) 6
E) 4
Is there a formula of some sort to solve this problem? Any help is appreciated.
Thanks,
-Andy
When the positive integer n is divided by 45, the remainder is 18.
In other words, n is multiple of 45 plus 18:
n = 45a + 18, where a is a nonnegative integer.
Simplifying n = 45a + 18, we get:
n = 45a + 18 = 9(5a + 2).
Thus, n must be a multiple of 9.
The correct answer is
B.
We can also TEST options for n.
If a=0, then n = 45a + 18 = 45*0 + 18 = 18.
Since 18 is not a multiple of 11, 7, or 4, eliminate A, C and E.
If a=1, then n = 45a + 18 = 45*1 + 18 = 63.
Since 63 is a not multiple of 6, eliminate D.
The correct answer is
B.
Last edited by
GMATGuruNY on Thu Dec 25, 2014 1:08 pm, edited 1 time in total.
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