BTGmoderatorLU wrote:What is the largest integer if the sum of three consecutive even integers is 318?

A. 100
B. 104
C. 106
D. 108
E. 111

Let x = the smallest value
So, x + 2 = the middle value
And x + 4 = the biggest value

The sum is 318
So, we can write x + (x+2) + (x+4) = 318
Simplify: 3x + 6 = 318
Subtract 6 from both sides to get: 3x = 312
Solve: x = 104
So, the SMALLEST value = 104
This means 106 is the MIDDLE value and 108 is the BIGGEST value

Answer: D

Cheers,
Brent

Hi All,

We're told that we have a group of 3 CONSECUTIVE, EVEN integers with a sum of 318. We're asked for the LARGEST integer. This question can be solved in number of different ways, including by TESTing THE ANSWERS.

Since 318 is well above 300 - and the integers are consecutive even integers - the largest number would need to be above 100. Let's TEST Answer D first...

Answer D: 108
IF..... the largest number is 108, then...
the other 2 numbers are 106 and 104.
The sum would be 104+106+108 = 318
This is an exact match for what we were told, so this MUST be the answer.

Final Answer: D

GMAT assassins aren't born, they're made,
Rich