BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

What is the largest integer if the sum of three consecutive

This topic has expert replies
Post new topic Post Reply
Previous Topic Next Topic
Source: — Problem Solving |

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 16207
Joined: Mon Dec 08, 2008 6:26 pm
Location: Vancouver, BC
Thanked: 5254 times
Followed by:1268 members
GMAT Score:770

by Brent@GMATPrepNow » Thu May 03, 2018 2:34 pm
BTGmoderatorLU wrote:What is the largest integer if the sum of three consecutive even integers is 318?

A. 100
B. 104
C. 106
D. 108
E. 111
Let x = the smallest value
So, x + 2 = the middle value
And x + 4 = the biggest value

The sum is 318
So, we can write x + (x+2) + (x+4) = 318
Simplify: 3x + 6 = 318
Subtract 6 from both sides to get: 3x = 312
Solve: x = 104
So, the SMALLEST value = 104
This means 106 is the MIDDLE value and 108 is the BIGGEST value

Answer: D

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
Image
Top

GMAT/MBA Expert

User avatar
Elite Legendary Member
Posts: 10392
Joined: Sun Jun 23, 2013 6:38 pm
Location: Palo Alto, CA
Thanked: 2867 times
Followed by:511 members
GMAT Score:800

by [email protected] » Thu May 03, 2018 4:35 pm
Hi All,

We're told that we have a group of 3 CONSECUTIVE, EVEN integers with a sum of 318. We're asked for the LARGEST integer. This question can be solved in number of different ways, including by TESTing THE ANSWERS.

Since 318 is well above 300 - and the integers are consecutive even integers - the largest number would need to be above 100. Let's TEST Answer D first...

Answer D: 108
IF..... the largest number is 108, then...
the other 2 numbers are 106 and 104.
The sum would be 104+106+108 = 318
This is an exact match for what we were told, so this MUST be the answer.

Final Answer: D

GMAT assassins aren't born, they're made,
Rich
Contact Rich at [email protected]
Image
Top
User avatar
GMAT Instructor
Posts: 15539
Joined: Tue May 25, 2010 12:04 pm
Location: New York, NY
Thanked: 13060 times
Followed by:1906 members
GMAT Score:790

by GMATGuruNY » Thu May 03, 2018 5:48 pm
BTGmoderatorLU wrote:What is the largest integer if the sum of three consecutive even integers is 318?

A. 100
B. 104
C. 106
D. 108
E. 111
Consecutive even integers constitute an EVENLY SPACED SET.
For any evenly spaced set, MEDIAN = AVERAGE.
In the problem at hand:
Median = Average = 318/3 = 106.
Since the median of the 3 consecutive even integers = 106, the greatest of the 3 consecutive even integers = 108.

The correct answer is D.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Top
User avatar
GMAT Instructor
Posts: 1462
Joined: Thu Apr 09, 2015 9:34 am
Location: New York, NY
Thanked: 39 times
Followed by:22 members

by Jeff@TargetTestPrep » Mon May 07, 2018 10:01 am
BTGmoderatorLU wrote:What is the largest integer if the sum of three consecutive even integers is 318?

A. 100
B. 104
C. 106
D. 108
E. 111
If we let n = the first even integer, then the next consecutive even integer is (n + 2), and the one after that is (n + 4). W create the equation:

n + n + 2 + n + 4 = 318

3n = 312

n = 104

So the largest integer is 104 + 4 = 108.

Answer: D

Jeffrey Miller
Head of GMAT Instruction
[email protected]

Image

See why Target Test Prep is rated 5 out of 5 stars on BEAT the GMAT. Read our reviews
Top
Post new topic Post Reply
• Page 1 of 1