What’s the area of the triangle in terms of P?

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by reachac » Mon Jul 21, 2008 6:35 am
Are the options correct?

I got an ans (P ^ 2)(sqrt3)/36

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by umaa » Mon Jul 21, 2008 6:39 am
Hey,
Right. even i got the same answer.

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by VP_Tatiana » Mon Jul 21, 2008 6:43 am
I also got what reachac got.

Draw a vertical line dividing the triangle in half. Now, 1/2 of the base is P/6. To find the height, look at one of the two 30-60-90 triangles you created. Remembering the proportion for this type of triangle tells you that the side opposite the 60 degree angle (the height) is sqrt3 times the side opposite the 30 degree angle, p/6. So, we have a height of P*sqrt3/6.

1/2 bh = (p/6)*(psqrt3/6) = (p^2)sqrt3/36
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by sudhir3127 » Mon Jul 21, 2008 9:12 am
Even i got P^2/(12sqrt 3)

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by parallel_chase » Mon Jul 21, 2008 1:47 pm
There is definitely something wrong with the answer choices or the question.

Even i got the same answer P^2/12sqrt3 or P^2sqrt3/36