smclean23 wrote:If x and y are integers, then 1/x+y CANNOT be equal to
(A) –1
(B) 1/2
(C) 0
(D) -1/2
(E) 1
How to solve?
C
I'm assuming you meant to write (1)/(x+y)
Because it would make more sense logically.
The only way for a fraction to be zero is if the numerator is also zero.
But in this problem it is not the case.
If (x+y) in this problem were to net to zero then the problem would be undefined. "(1)/(0) = undefined"
So answer is "C"
