What is the value of (2a+b)/(a+b)?

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What is the value of (2a+b)/(a+b)?

by missrochelle » Wed Aug 25, 2010 6:48 am
(1) 3a/(a+b) = 7
(2) a+b = 3

Solution:
3a/(a+b)=7
=>a/a+b=7/3
=> 1+a/a+b=1+7/3
=>2a+b/a+b=10/7
1 is sufficient
It's evident that 2 is not by itself sufficient. Answer is A.


Can someone please explain the factoring of statement A. If 3 is in the numerator - how are we dividing each side by 3 to get rid of it? Furthermore in the last step, how do you go from "1+a/a" to "2a+b/a" ?
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by kmittal82 » Wed Aug 25, 2010 7:25 am
Think of it this way

2a+b/a+b = (a + a + b )/ (a +b) = [a/(a+b)] + 1
If we find a/(a+b), we can answer the question.

Statement 1 says

3a/(a+b) = 7 => a/(a+b) = 7/3

This gives us enough information to answer the question.

>If 3 is in the numerator - how are we dividing each side by 3 to get rid of it?
if a/b = c/d, then you can multiply or divide both by the same value i.e. k*a/b = k*c/d

>Furthermore in the last step, how do you go from "1+a/a" to "2a+b/a" ?
1 + a/(a+b) = [(a+b) + a] / (a+b) = (2a+b)/(a+b)

Its the same as saying:

1 + 7/3 = [3+7]/3 = 10/3

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by missrochelle » Wed Aug 25, 2010 7:39 am
That makes a lot of sense. It's hard to see sometimes when they want you to "separate" out the variables. How did you know to rewrite the equation in order to separate the a+b equation? Seems like it would be pattern recognition -- if you see two common variables the GMAT is "asking" you to factor them out?

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by kmittal82 » Wed Aug 25, 2010 7:58 am
missrochelle wrote:That makes a lot of sense. It's hard to see sometimes when they want you to "separate" out the variables. How did you know to rewrite the equation in order to separate the a+b equation? Seems like it would be pattern recognition -- if you see two common variables the GMAT is "asking" you to factor them out?
There's no pattern as such.

If you want, you can do it the long way as well, by using (1) to find a in terms of b (or vice versa) and putting those values in the original question.

Generally when I see a division involving variables, I think about breaking down the division automatically (as the above case). I guess there is no hard and fast rule, just more practice :)

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by Brian@VeritasPrep » Wed Aug 25, 2010 12:43 pm
Hey guys,

Great thread - and I love the explanation, kmittal!

Since we're talking strategy on this one, I wanted to point out that this question lends itself really well to a DS strategy that I think is really important and useful:

If both statements together make it particularly easy to solve the problem, you can probably do it with one statement alone and should work to see which one can do it.

Essentially, the GMAT has two ways to get you a wrong answer on the GMAT:

1) You think you have enough information but you actually don't

2) You think you don't have enough information but you actually do

The first is full of assumptions, forgetting to consider 0, etc.

The second is more subtle and can lend itself to higher difficulty problems like this one. Would most people have the patience to factor out Statement 1, or to play with the algebra for >5 steps to simplify? Probably not, particularly given the time pressure of this test. But when you look at both statements together, it's far too easy to pick 'C'. That should be your clue that it's worth putting in the extra time to work out the algebra in statement 1.

Whether you factor as kmittal did, or start to work through the equation by multiplying out the denominator, your guiding principle should be "both together are too easy, so it's worth the extra time to try to do it with this one alone". It's a great investment of your time at that point.


I worked through the algebra on this one:

3a/(a+b) = 7
3a = 7a + 7b
-4a = 7b
a = -7/4 b

Now that I know I can solve for a in terms of b, I can look at the initial question and see if that's enough (or if I need to do any additional work):

What is (2a + b)/(a+b)?

If I can express both the numerator and denominator in terms of b:

[2(-7/4 b) + b] / (-7/4 b + b)

Then I'll be able to get a b term on top and a b term on bottom, and then divide out the bs to get a number. Therefore, statement 1 alone is sufficient.
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by kmittal82 » Wed Aug 25, 2010 2:34 pm
Brian@VeritasPrep wrote:Hey guys,

Great thread - and I love the explanation, kmittal!

Since we're talking strategy on this one, I wanted to point out that this question lends itself really well to a DS strategy that I think is really important and useful:

If both statements together make it particularly easy to solve the problem, you can probably do it with one statement alone and should work to see which one can do it.

Essentially, the GMAT has two ways to get you a wrong answer on the GMAT:

1) You think you have enough information but you actually don't

2) You think you don't have enough information but you actually do

The first is full of assumptions, forgetting to consider 0, etc.

The second is more subtle and can lend itself to higher difficulty problems like this one. Would most people have the patience to factor out Statement 1, or to play with the algebra for >5 steps to simplify? Probably not, particularly given the time pressure of this test. But when you look at both statements together, it's far too easy to pick 'C'. That should be your clue that it's worth putting in the extra time to work out the algebra in statement 1.

Whether you factor as kmittal did, or start to work through the equation by multiplying out the denominator, your guiding principle should be "both together are too easy, so it's worth the extra time to try to do it with this one alone". It's a great investment of your time at that point.


I worked through the algebra on this one:

3a/(a+b) = 7
3a = 7a + 7b
-4a = 7b
a = -7/4 b

Now that I know I can solve for a in terms of b, I can look at the initial question and see if that's enough (or if I need to do any additional work):

What is (2a + b)/(a+b)?

If I can express both the numerator and denominator in terms of b:

[2(-7/4 b) + b] / (-7/4 b + b)

Then I'll be able to get a b term on top and a b term on bottom, and then divide out the bs to get a number. Therefore, statement 1 alone is sufficient.
An excellent tip Brian, thanks :). Indeed I have also noticed, if combining option 1 and 2 leads to an answer quickly, more often than not you only need one equation equation.

Maybe this is a bit out of the scope of this discussion, but on a DS question, if option 1 and 2 are each enough to solve the problem, however they give different numerical answers, is this an indication you have done something wrong? For e.g., if the question asks you "Is x>0?" (1) x > 6 (2) x =3

Both (1) and (2) individually are enough to answer this, however they each give a different answer for x.

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by Ian Stewart » Wed Aug 25, 2010 9:21 pm
Just a couple of things here:
kmittal82 wrote:
Maybe this is a bit out of the scope of this discussion, but on a DS question, if option 1 and 2 are each enough to solve the problem, however they give different numerical answers, is this an indication you have done something wrong? For e.g., if the question asks you "Is x>0?" (1) x > 6 (2) x =3

Both (1) and (2) individually are enough to answer this, however they each give a different answer for x.
The two statements in any *real* GMAT DS question always must be logically consistent; they can never contradict each other. So you could never see, on the real GMAT, a question like the one you suggest. You may, however, encounter some poorly designed practice questions which do not observe this principle.
missrochelle wrote:(1) 3a/(a+b) = 7

Solution:
3a/(a+b)=7
=>a/a+b=7/3
=> 1+a/a+b=1+7/3
=>2a+b/a+b=10/7
1 is sufficient

Can someone please explain the factoring of statement A. If 3 is in the numerator - how are we dividing each side by 3 to get rid of it? Furthermore in the last step, how do you go from "1+a/a" to "2a+b/a" ?
That solution is more confusing than helpful. It's missing brackets in *many* places, which must make it very difficult to follow unless you knew in advance what the writer was doing (in which case you wouldn't need to read a solution at all!). I wouldn't spend any time on it, in any case; there are more worthwhile solutions earlier in this thread.
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by frank1 » Fri Nov 05, 2010 7:34 pm
Ian Stewart wrote:Just a couple of things here:
kmittal82 wrote:Solution:
3a/(a+b)=7
=>a/a+b=7/3
=> 1+a/a+b=1+7/3
=>2a+b/a+b=10/7
1 is sufficient

Can someone please explain the factoring of statement A. If 3 is in the numerator - how are we dividing each side by 3 to get rid of it? Furthermore in the last step, how do you go from "1+a/a" to "2a+b/a" ?
That solution is more confusing than helpful. It's missing brackets in *many* places, which must make it very difficult to follow unless you knew in advance what the writer was doing (in which case you wouldn't need to read a solution at all!). I wouldn't spend any time on it, in any case; there are more worthwhile solutions earlier in this thread.
I agree guru
When i first looked at the things,it was just like some body is trying to convert 3a into 2a(which are never same)
The zist here seems to be
one equation with a and b

st 1)with a and b from where we can express one as another (no trap) so sufficient
st 2)with a and b but there is a trap and plays with perceiption that when there are 2 variables and when we have 2 eqs it is sufficient (-b+b=0)

thanks
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