BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

what is the sum of the m and n?

Expert replies
Source: — Data Sufficiency |

by GMATGuruNY » Mon Sep 14, 2015 6:56 pm
vdm wrote:If the greatest common factor of two integers, m and n, is 56 and the least common multiple is 840, what is the sum of the m and n?

(1) m is not divisible by 15.
(2) n is divisible by 15
The GCF of m and n is composed of all of the prime factors that divide into both m and n.
56 = 2*2*2*7.
Thus, 2*2*2*7 divides into both m and n.

The LCM of m and n is composed of all of the prime factors that divide into only m, into only n, or into both m and n.
840 = 2*2*2*3*5*7.
Since 2*2*2*7 divides into both m and n, 3 and 5 each divide into only m or into only n.

Use Venn Diagrams to organize the data.
The following four cases are possible:
Image

Statement 1: m is not divisible by 15
Here, Cases 2, 3 and 4 are possible.
In Case 2, m = 2*2*2*7 and n= 2*2*2*3*5*7.
In Case 3, m = 2*2*2*3*7 and n = 2*2*2*5*7.
Since the value of m+n will be different in each case, INSUFFICIENT.

Statement 2: n is divisible by 15
Here, only Case 2 is possible.
In Case 2, m = 2*2*2*7 and n= 2*2*2*3*5*7.
Since the value of m+n can be determined, SUFFICIENT.

The correct answer is B.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Join the discussion

by vdm » Mon Sep 14, 2015 9:42 pm
Thank you, Mitch! Your explanation made it real simple to understand.
Join the discussion

by Max@Math Revolution » Tue Sep 15, 2015 8:43 am
Forget conventional ways of solving math questions. In DS, Variable approach is the easiest and quickest way to find the answer without actually solving the problem.
Remember equal number of variables and independent equations ensures a solution.


If the greatest common factor of two integers, m and n, is 56 and the least common multiple is 840, what is the sum of the m and n?

(1) m is not divisible by 15.
(2) n is divisible by 15

Transforming the original condition and the question we have (m,n)=(56*3,56*5),(56*1,56*15),(56*15*56*1),(56*5,56*3). Finding out m automatically gives us n, therefore we have 2 variables and thus we need 2 equations to match the number of variables and equations. Since there is 1 each in 1) and 2), D is likely the answer.

In case of 1), (m,n)=(56*3,56*5),(56*1,56*15),(56*5,56*3) therefore the answer is not unique and the condition is not sufficient.
In case of 2), (m,n)=(56*1,56*15) is unique, therefore the condition is sufficient. Thus the answer is B.

Normally for cases where we need 1 more equation, such as original conditions with 1 variable, or 2 variables and 1 equation, or 3 variables and 2 equations, we have 1 equation each in both 1) and 2). Therefore D has a high chance of being the answer, which is why we attempt to solve the question using 1) and 2) separately. Here, there is 59 % chance that D is the answer, while A or B has 38% chance. There is 3% chance that C or E is the answer for the case. Since D is most likely to be the answer according to DS definition, we solve the question assuming D would be our answer hence using 1) and 2) separately. Obviously there may be cases where the answer is A, B, C or E.

Math Revolution : Finish GMAT Quant Section with 10 minutes to spare
The one-and-only World's First Variable Approach for DS and IVY Approach for PS with ease, speed and accuracy.
Unlimited Access to over 120 free video lessons - try it yourself (https://www.mathrevolution.com/gmat/lesson)
See our Youtube demo (https://www.youtube.com/watch?v=R_Fki3_2vO8)
Join the discussion