Statement 1=> n is a multiple of 2.
This means that 'n' is even when '9' is raised to an even number.
Also, 10 is also an even number and when an even number is divided by even number, we have remainder = 0.
$$e.g\ if\ n=2;\ 9^2-1=80;\ \ \ \ \ \ So,\ \frac{80}{10}=8\ remainder\ 0$$
$$e.g\ if\ n=4;\ 9^4-1=6560;\ \ \ \ \ \ So,\ \frac{6560}{10}=656\ \ remainder\ 0$$
Hence, statement 1 is SUFFICIENT.
Statement 2=> n is a multiple of 3.
This means that 'n' can be either an even or odd number since multiples of 3 can either be even or odd (e.g 3, 6, 9, 12).
So, when 9 is raised to any number (even or odd) in the original expression, we should have a remainder of zero (0) for statement 2 to be sufficient.
$$e.g\ if\ n=3;\ 9^3-1=728;\ \ \ \ \ \ So,\ \frac{728}{10}=72\ \ remainder\ 8$$
$$e.g\ if\ n=6;\ 9^6-1=531441;\ \ \ \ \ \ So,\ \frac{531440}{10}=53144\ \ remainder\ 0$$
From the expression above, with n=odd, the remainder is not zero but with n=even, we have the remainder to be zero. Since the multiple of 3 cannot totally give us a remainder zero (0), then statement 2 is NOT SUFFICIENT.
Therefore, only statement 1 alone is SUFFICIENT. Hence, option A is the current answer.