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What is the minimum value of x*y^2 ?

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by bpgen » Wed Jun 16, 2010 7:03 pm
if -1/2<= x<=-1/3 and -1/4<= y<=-1/5, What is the minimum value of x*y^2 ?

A) -1/75
B) -1/50
C) -1/48
D) -1/32
E) -1/16
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Source: — Problem Solving |

by kvcpk » Wed Jun 16, 2010 7:11 pm
IMO A

what is OA?
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by bpgen » Wed Jun 16, 2010 7:12 pm
OA- D
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by selango » Wed Jun 16, 2010 7:52 pm
To find the minimum value,take the least value of x and y.

(-1/2)*(-1/4)^2

-1/32
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by kvcpk » Wed Jun 16, 2010 8:08 pm
selango wrote:To find the minimum value,take the least value of x and y.

(-1/2)*(-1/4)^2

-1/32
Yeah.. you are rite.. I messed it up.. least value of Y is -1/4.
so answer should be -1/32
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