The basic one-way air fare for a child aged between 3 and 10 years costs half the regular fare for an adult plus a reservation charge that is the same on the child's ticket as on the adult's ticket. One reserved ticket for an adult costs $216 and the cost of a reserved ticket for an adult and a child (aged between 3 and 10) costs $327. What is the basic fare for the journey for an adult?
A $111
B $52.5
C $210
D $58.5
E $6
OA: C
What is the basic fare for the journey for an adult?
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We can PLUG IN THE ANSWERS, which represent the basic adult fare.Musicat wrote:The basic one-way air fare for a child aged between 3 and 10 years costs half the regular fare for an adult plus a reservation charge that is the same on the child's ticket as on the adult's ticket. One reserved ticket for an adult costs $216 and the cost of a reserved ticket for an adult and a child (aged between 3 and 10) costs $327. What is the basic fare for the journey for an adult?
A $111
B $52.5
C $210
D $58.5
E $6
When the correct answer choice is plugged in, the total cost for a child's ticket and a reserved adult ticket = 327.
Since a reserved adult ticket = 216, it seems unlikely that the price of a basic adult ticket would be as low as 6, 52.5, 58.6, or 111.
The correct answer is probably C.
C: 210
Here:
Reservation charge = (reserved adult fare) - (basic adult fare) = 216 - 210 = 6.
Basic child fare = (half basic adult fare) + (reservation charge) = (1/2)(210) + 6 = 111.
Basic child fare + reserved adult fare = 111 + 216 = 327.
Success!
The correct answer is C.
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Hi Musicat,
I'm a big fan of TESTing THE ANSWERS (the approach Mitch used) on this question. It can also be solved Algebraically, using a 'system' of equations:
T = price of adult fare
F = cost of reservation charge
Adult Ticket = T + F
Kid's Ticket = (T/2) + F
1 reserved Adult Ticket = T + F = 216
1 Adult + 1 Kid = (3T/2) + 2F = 327
From here, you have two variables and two unique equations, so you can solve for both variables. The question asks us for the value of T.
[(3T/2) + 2F] - [T + F] = 327 - 216
T/2 + F = 111
(T + F) - (T/2 + F) = 216 - 111 = 105
T/2 = 105
T = 210
Final Answer: C
GMAT assassins aren't born, they're made,
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I'm a big fan of TESTing THE ANSWERS (the approach Mitch used) on this question. It can also be solved Algebraically, using a 'system' of equations:
T = price of adult fare
F = cost of reservation charge
Adult Ticket = T + F
Kid's Ticket = (T/2) + F
1 reserved Adult Ticket = T + F = 216
1 Adult + 1 Kid = (3T/2) + 2F = 327
From here, you have two variables and two unique equations, so you can solve for both variables. The question asks us for the value of T.
[(3T/2) + 2F] - [T + F] = 327 - 216
T/2 + F = 111
(T + F) - (T/2 + F) = 216 - 111 = 105
T/2 = 105
T = 210
Final Answer: C
GMAT assassins aren't born, they're made,
Rich