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What is the average of the terms in set J? (1) The sum of

Expert replies
by BTGmoderatorDC » Sun Sep 08, 2019 6:29 pm

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Answers

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B

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D

E

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Difficulty—

What is the average of the terms in set J?

(1) The sum of any three terms in set J is 21.
(2) Set J consists of 12 total terms.

OA A

Source: Veritas Prep
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Source: — Data Sufficiency |

by swerve » Mon Sep 09, 2019 3:15 am
BTGmoderatorDC wrote:What is the average of the terms in set J?

(1) The sum of any three terms in set J is 21.
(2) Set J consists of 12 total terms.

OA A

Source: Veritas Prep
Statement 1:
Suppose set has 4 terms a,b, c and d

\(a+b+c=21\)
\(b+c+d=21\)
\(a+b+d=21\)

Above situation is only possible when all the numbers are same.
hence Mean\(=7\). Sufficient \(\color{green}\checkmark\)

Statement 2:
Doesn't speak about the numbers in set. Insufficient \(\Large{\color{red}{\times}}\)

Therefore, __A__
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by Brent@GMATPrepNow » Mon Sep 09, 2019 5:56 am
BTGmoderatorDC wrote:What is the average of the terms in set J?

(1) The sum of any three terms in set J is 21.
(2) Set J consists of 12 total terms.

OA A

Source: Veritas Prep
Target question: What is the average of the terms in set J?

Statement 1: The sum of any three terms in set J is 21.
This is a very powerful statement, because it tells us that all of the numbers in the set are equal.
Let's let a,b and c be three of the numbers in set J.
We know that a + b + c = 21
Notice that if I replace ANY of these three values (a,b or c) with d, the sum must still be 21.
This tells us that a, b and c must all equal d.
Using similar logic, I can show that ALL of the numbers in the set must equal d, which means all of the numbers in the set must be equal.
If all of the numbers are equal, then EVERY number must equal 7, which means the average of set J MUST equal 7
Since we can answer the target question with certainty, statement 1 is SUFFICIENT

Statement 2: Set J consists of 12 total terms
There are several possible scenarios that satisfy this statement. Here are two.
Case a: J = {2,2,2,2,2,2,2,2,2,2,2,2}, in which case the average of set J = 2
Case b: J = {1,1,1,1,1,1,1,1,1,1,1,1}, in which case the average of set J = 1
Since we cannot answer the target question with certainty, statement 2 is NOT SUFFICIENT

Answer: A

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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