Excellent answer!
Let me see if I can reinforce this for myself and add to this:
1) If x(max)=5
and
y(max)=5
x= (5,0)
y= (0,5)
The distance between (0,0) and X(5,0) is 5.
The distance between (0,0) and Y(0,5) is 5.
Drawing a straight line between X and Y results in the distance being 5sqrt 2.
2) Next make X negative which results in (-5,0) but maintain Y as positive such that it is (0,5).
Once again the distance between X and Y is 5sqrt 2.
3) Next Make X and Y both negative such that X is (-5,0) and Y is (0,-5) resulting in a distance of 5sqrt2.
4) Lastly make X positive but Y negative such that X is (5,0) and Y is (0,-5). The distance is 5sqrt2.
Since all sides are equal, (5sqrt2), it forms a square. The area would be (5sqrt2)^2 = (5)^2 * (sqr2)^2 = 25 * 2 = 50.
gmat740 wrote:this one is pretty straight forward once you draw the figure on paper
X(max) = 5( i.e max value of x is 5)
Y(max) = 5
so, plot both X and Y on co-ordinate plane and join X and Y. You will get a straight line of length 5*sqrt(2)
Over here were took
x =+
y =+
now similarly, we have get 4 sets of straight lines( rather a square) of length 5*sqrt(2)
so, area = [5*sqrt(2)]^2
= 25*2 = 50
Hope this Helps
