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What is the 99th digit after the decimal point in the

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by BTGmoderatorDC » Tue Aug 07, 2018 7:49 pm

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What is the 99th digit after the decimal point in the decimal expansion of 2/9 + 3/11?

A. 1
B. 2
C. 4
D. 7
E. 9

OA C

Source: Manhattan GMAT
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Source: — Problem Solving |

by Jay@ManhattanReview » Tue Aug 07, 2018 9:12 pm
BTGmoderatorDC wrote:What is the 99th digit after the decimal point in the decimal expansion of 2/9 + 3/11?

A. 1
B. 2
C. 4
D. 7
E. 9

OA C

Source: Manhattan GMAT
2/9 = 0.2222...; we see that the 99th digit would be '2.'
3/11 = 0.2727...; we see that the digits at odd places are 2,' while that at even places are '7.' Since 99 is odd, the 99th digit would be '7.'

Thus, the 99th digit after the decimal point in the decimal expansion of 2/9 + 3/11 = 2 + 2 = 4.

The correct answer: C

Hope this helps!

-Jay
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by swerve » Wed Aug 08, 2018 10:17 am
$$\frac{2}{9}=0.2222222...............2$$
$$\frac{3}{11}=0.27272727...............27$$
Addition (does not have carries)
$$\frac{2}{9}+\frac{3}{11}=0.49494949..........49$$
Odd's have 4.

99th would have 4. Therefore, C is the correct answer. Regards!
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by Scott@TargetTestPrep » Sun Aug 26, 2018 6:35 pm
BTGmoderatorDC wrote:What is the 99th digit after the decimal point in the decimal expansion of 2/9 + 3/11?

A. 1
B. 2
C. 4
D. 7
E. 9
2/9 + 3/11 = 22/99 + 27/99 = 49/99 = 0.494949....

SInce each odd-positioned digit to the right of the decimal point has a value of 4, the 99th digit is 4.

Alternate Solution:

We see that 2/9 = 0.222... and 3/11 = 0.272727...

If we add the two decimal expressions, we see that we obtain 0.494949... Since all the odd-positioned digits to the right of the decimal point have a value of of 4, the 99th digit is 4.

Answer: C

Scott Woodbury-Stewart
Founder and CEO
[email protected]

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