A. 1/2
B. 2/5
C. 3/5
D. 4/5
E. 5/8
Answer is E
Can someone please give me a simple solution? I keep picking C, and obviously I am wrong
Thanks so so much!!
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What fraction of all the boxes..?? :s
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gmatpup
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At a loading dock, each worker on the night crew loaded 3/4 as many boxes as each worker on the day crew. If the night crew has 4/5 as many workers as the day crew, what fraction of all the boxes loaded by the two crews did the day crew load?
A. 1/2
B. 2/5
C. 3/5
D. 4/5
E. 5/8
Answer is E
Can someone please give me a simple solution? I keep picking C, and obviously I am wrong
Thanks so so much!!
A. 1/2
B. 2/5
C. 3/5
D. 4/5
E. 5/8
Answer is E
Can someone please give me a simple solution? I keep picking C, and obviously I am wrong
Thanks so so much!!
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Anurag@Gurome
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Here is a solution posted by Rahul : https://www.beatthegmat.com/ps-138-t68828.html#310799
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rijul007
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gmatpup wrote:This question is from the OG 12th edition so it is definitely correct.. I just don't see how to get answer E
I got it where we went wrong
At a loading dock, each worker on the night crew loaded 3/4 as many boxes as each worker on the day crew. If the night crew has 4/5 as many workers as the day crew, what fraction of all the boxes loaded by the two crews did the day crew load?
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GMATGuruNY
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I posted a solution here:gmatpup wrote:At a loading dock, each worker on the night crew loaded 3/4 as many boxes as each worker on the day crew. If the night crew has 4/5 as many workers as the day crew, what fraction of all the boxes loaded by the two crews did the day crew load?
A. 1/2
B. 2/5
C. 3/5
D. 4/5
E. 5/8
Answer is E
Can someone please give me a simple solution? I keep picking C, and obviously I am wrong
Thanks so so much!!
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Since both of the ratios are in the form night crew to day crew I just assumed the day crew consists of 5 workers, each of which loads only one box per shift. With those assumptions:gmatpup wrote:At a loading dock, each worker on the night crew loaded 3/4 as many boxes as each worker on the day crew. If the night crew has 4/5 as many workers as the day crew, what fraction of all the boxes loaded by the two crews did the day crew load?
A. 1/2
B. 2/5
C. 3/5
D. 4/5
E. 5/8
Answer is E
Can someone please give me a simple solution? I keep picking C, and obviously I am wrong
Thanks so so much!!
Day crew= 5 * 1 = 5 boxes.
Night crew= 4 * 3/4 = 3 boxes.
Total boxes for both shifts = 8.
Total boxes by day crew = 5.
Answer = [spoiler]5/8 (E)[/spoiler]
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smackmartine
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IMO E
Bn=Boxes loaded at night
Bd=Boxes loaded during the day
Wn=# of workers at night
Wd=# of workers during the day
To answer : Bd/(Bd+Bn) ?
-----------------------
Boxes loaded per worker at night =Bn/Wn
Boxes loaded per worker during day =Bd/Wd
Given that, Wn=4/5(Wd) and Bn/Wn = 3/4(Bd/Wd)
Combining both , we get Bn/Bd = 3/5
Adding 1 both sides, we get (Bn+Bd)/Bd = 8/5 ,so Bd/(Bn+Bd) = 5/8
Bn=Boxes loaded at night
Bd=Boxes loaded during the day
Wn=# of workers at night
Wd=# of workers during the day
To answer : Bd/(Bd+Bn) ?
-----------------------
Boxes loaded per worker at night =Bn/Wn
Boxes loaded per worker during day =Bd/Wd
Given that, Wn=4/5(Wd) and Bn/Wn = 3/4(Bd/Wd)
Combining both , we get Bn/Bd = 3/5
Adding 1 both sides, we get (Bn+Bd)/Bd = 8/5 ,so Bd/(Bn+Bd) = 5/8
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ArunangsuSahu
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Simple Solution Approach:
Clue: Always try to take a number that divides the denominator completely.
So Let's assume No.Of day workers = 5
and Load taken by each day worker =4
Total Load Taken by day worker =5*4=20
There for Total Load Taken by night worker = 4*3=12
So Total load by two crew=20+12=32
Reqd fraction = day load/Total Load = 20/32=5/8
Ans:(E)
Clue: Always try to take a number that divides the denominator completely.
So Let's assume No.Of day workers = 5
and Load taken by each day worker =4
Total Load Taken by day worker =5*4=20
There for Total Load Taken by night worker = 4*3=12
So Total load by two crew=20+12=32
Reqd fraction = day load/Total Load = 20/32=5/8
Ans:(E)
