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What fraction of all the boxes..?? :s

Expert replies
by gmatpup » Sat Nov 12, 2011 7:45 am
At a loading dock, each worker on the night crew loaded 3/4 as many boxes as each worker on the day crew. If the night crew has 4/5 as many workers as the day crew, what fraction of all the boxes loaded by the two crews did the day crew load?

A. 1/2

B. 2/5

C. 3/5

D. 4/5

E. 5/8

Answer is E

Can someone please give me a simple solution? I keep picking C, and obviously I am wrong :(

Thanks so so much!!
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Source: — Problem Solving |

by rijul007 » Sat Nov 12, 2011 8:01 am
am too getting C again and again

can you check your source again...
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by gmatpup » Sat Nov 12, 2011 8:07 am
This question is from the OG 12th edition so it is definitely correct.. I just don't see how to get answer E
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by Anurag@Gurome » Sat Nov 12, 2011 8:08 am
Here is a solution posted by Rahul : https://www.beatthegmat.com/ps-138-t68828.html#310799
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by rijul007 » Sat Nov 12, 2011 8:19 am
gmatpup wrote:This question is from the OG 12th edition so it is definitely correct.. I just don't see how to get answer E

I got it where we went wrong

At a loading dock, each worker on the night crew loaded 3/4 as many boxes as each worker on the day crew. If the night crew has 4/5 as many workers as the day crew, what fraction of all the boxes loaded by the two crews did the day crew load?
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by GMATGuruNY » Sat Nov 12, 2011 12:19 pm
gmatpup wrote:At a loading dock, each worker on the night crew loaded 3/4 as many boxes as each worker on the day crew. If the night crew has 4/5 as many workers as the day crew, what fraction of all the boxes loaded by the two crews did the day crew load?

A. 1/2

B. 2/5

C. 3/5

D. 4/5

E. 5/8

Answer is E

Can someone please give me a simple solution? I keep picking C, and obviously I am wrong :(

Thanks so so much!!
I posted a solution here:

https://www.beatthegmat.com/algebra-appl ... tml#353208
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by JohnRapp » Sat Nov 12, 2011 1:46 pm
gmatpup wrote:At a loading dock, each worker on the night crew loaded 3/4 as many boxes as each worker on the day crew. If the night crew has 4/5 as many workers as the day crew, what fraction of all the boxes loaded by the two crews did the day crew load?

A. 1/2

B. 2/5

C. 3/5

D. 4/5

E. 5/8

Answer is E

Can someone please give me a simple solution? I keep picking C, and obviously I am wrong :(

Thanks so so much!!
Since both of the ratios are in the form night crew to day crew I just assumed the day crew consists of 5 workers, each of which loads only one box per shift. With those assumptions:

Day crew= 5 * 1 = 5 boxes.
Night crew= 4 * 3/4 = 3 boxes.

Total boxes for both shifts = 8.
Total boxes by day crew = 5.

Answer = [spoiler]5/8 (E)[/spoiler]
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by smackmartine » Sat Nov 12, 2011 3:19 pm
IMO E
Bn=Boxes loaded at night
Bd=Boxes loaded during the day

Wn=# of workers at night
Wd=# of workers during the day

To answer : Bd/(Bd+Bn) ?
-----------------------
Boxes loaded per worker at night =Bn/Wn
Boxes loaded per worker during day =Bd/Wd

Given that, Wn=4/5(Wd) and Bn/Wn = 3/4(Bd/Wd)

Combining both , we get Bn/Bd = 3/5
Adding 1 both sides, we get (Bn+Bd)/Bd = 8/5 ,so Bd/(Bn+Bd) = 5/8
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It takes time and effort to explain, so if my comment helped you please press Thanks button :)
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by ArunangsuSahu » Sun Nov 13, 2011 8:06 am
Simple Solution Approach:

Clue: Always try to take a number that divides the denominator completely.
So Let's assume No.Of day workers = 5
and Load taken by each day worker =4

Total Load Taken by day worker =5*4=20
There for Total Load Taken by night worker = 4*3=12
So Total load by two crew=20+12=32

Reqd fraction = day load/Total Load = 20/32=5/8

Ans:(E)
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