A focus group is currently made up of \(x\) men and \(y\)

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BTGmoderatorLU: Moderator; Posts: 2505; Joined: Sun Oct 15, 2017 1:50 pm; Followed by:6 members

A focus group is currently made up of \(x\) men and \(y\)

by BTGmoderatorLU » Sat Oct 19, 2019 1:59 am

Source: Princeton Review

A focus group is currently made up of x men and y women. If 2 men and 4 women are added to the group, and if one person is selected at random from the larger focus group, then what is the probability that a man is selected?

A. x/(x + 2)
B. x/(x + y)
C. (x + 2)/(x + y + 2)
D. (y + 4)/(x + y + 6)
E. (x + 2)/(x + y + 6)

The OA is E

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Source: Beat The GMAT — Problem Solving | Sat Oct 19, 2019 1:59 am

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Jay@ManhattanReview: GMAT Instructor; Posts: 3008; Joined: Mon Aug 22, 2016 6:19 am; Location: Grand Central / New York; Thanked: 470 times; Followed by:34 members

by Jay@ManhattanReview » Mon Oct 21, 2019 4:53 am

BTGmoderatorLU wrote:Source: Princeton Review

A focus group is currently made up of x men and y women. If 2 men and 4 women are added to the group, and if one person is selected at random from the larger focus group, then what is the probability that a man is selected?

A. x/(x + 2)
B. x/(x + y)
C. (x + 2)/(x + y + 2)
D. (y + 4)/(x + y + 6)
E. (x + 2)/(x + y + 6)

The OA is E

With the addition of 2 men and 4 women, there are (x + 2) men out of (x + y + 6) persons

Thus, the probability that a man is selected = (x + 2)/(x + y + 6)

The correct answer: E

Hope this helps!

-Jay
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swerve: Legendary Member; Posts: 2499; Joined: Sun Oct 29, 2017 2:04 pm; Followed by:6 members

by swerve » Wed Oct 23, 2019 5:54 am

BTGmoderatorLU wrote:Source: Princeton Review

A focus group is currently made up of x men and y women. If 2 men and 4 women are added to the group, and if one person is selected at random from the larger focus group, then what is the probability that a man is selected?

A. x/(x + 2)
B. x/(x + y)
C. (x + 2)/(x + y + 2)
D. (y + 4)/(x + y + 6)
E. (x + 2)/(x + y + 6)

The OA is E

\(x\) men
\(y\) women

\(x+2+y+4\) is the total
\(=x+y+6\)

\(x+2\) is the number of men

so \(\frac{x + 2}{x + y + 6}\, \Rightarrow\) E

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Scott@TargetTestPrep: GMAT Instructor; Posts: 8086; Joined: Sat Apr 25, 2015 10:56 am; Location: Los Angeles, CA; Thanked: 43 times; Followed by:29 members

by Scott@TargetTestPrep » Wed Oct 23, 2019 5:59 pm

BTGmoderatorLU wrote:Source: Princeton Review

A focus group is currently made up of x men and y women. If 2 men and 4 women are added to the group, and if one person is selected at random from the larger focus group, then what is the probability that a man is selected?

A. x/(x + 2)
B. x/(x + y)
C. (x + 2)/(x + y + 2)
D. (y + 4)/(x + y + 6)
E. (x + 2)/(x + y + 6)

The OA is E

After the addition of the new members, there are (x + 2) men and (y + 4) women in the group, and so the total number of individuals in the focus group is now (x + y + 6). Thus, the probability that a man is selected is (x + 2)/(x + y + 6).

Answer: E

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