BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATBootcamp Starts Sep 28
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE BOOTCAMP

Live Online Bootcamp Class with Top GMAT Expert Chris Peckover

15 live classes from Sep 28, 2026

Schedule
Mon to Fri · 7:00 to 10:00 PM ET
Included
Live classes + 6 months of TTP OnDemand
  • Boost your GMAT score in less than one month in a live online class
  • 6 months access to TTP OnDemand video courses included
View bootcamp & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Line Intersection

Expert replies
Source: — Data Sufficiency |

by lunarpower » Thu Apr 24, 2008 2:08 am
i'm not sure i understand what statements (1) and (2) are supposed to say here; please post clear and unambiguous versions of statements (1) and (2).

--

in any case, here's a start:

since you're looking for an intersection point, you know that the y coordinates have to be the same. therefore, ax - b must equal x^2 + b, which means that ax - x^2 = 2b, or, x(a - x) = 2b.

can't get any farther without the statements.
Ron has been teaching various standardized tests for 20 years.

--

Pueden hacerle preguntas a Ron en castellano
Potete chiedere domande a Ron in italiano
On peut poser des questions à Ron en français
Voit esittää kysymyksiä Ron:lle myös suomeksi

--

Quand on se sent bien dans un vêtement, tout peut arriver. Un bon vêtement, c'est un passeport pour le bonheur.

Yves Saint-Laurent

--

Learn more about ron
Join the discussion

by Stuart@KaplanGMAT » Thu Apr 24, 2008 11:56 am
Whenever you post inequalities, make sure you click the "disable HMTL in this post" box below the text window. HTML uses < and > for tags and if you have HTML on your inequalities will get all squishy!

Similarly, if you ever see a smiley in one of your posts and didn't mean to put one there, it's probably because you typed 8) and didn't disable Smilies.
Image

Stuart Kovinsky | Kaplan GMAT Faculty | Toronto

Kaplan Exclusive: The Official Test Day Experience | Ready to Take a Free Practice Test? | Kaplan/Beat the GMAT Member Discount
BTG100 for $100 off a full course
Join the discussion

by mayank_gupta123 » Tue Oct 14, 2008 12:41 pm
Interesting question!

If there is at all an intersection, it would be a single point (obvious)

In that case

=> aX - b = X2 + b

=> X2 – aX + 2b = 0


For a real solution of X,

i.è. B2 – 4AC > 0



i.e. (-a)2 – 4 * 2b >0

i.e. b < a2/8



Irrespective of any sign of a, if b is less than zero, that would do the needful, therefore B should be the right answer.


Regards,
Mayank
Join the discussion

by cubicle_bound_misfit » Tue Oct 14, 2008 9:33 pm
mayank,

let go parabola but whenever a single degree equation cuts an n degree equation there will be a n point cut.
Cubicle Bound Misfit
Join the discussion

by 69aero69 » Fri Oct 17, 2008 5:44 am
since I cannot see the options, I don't know the final response but here is a way to solve it:

x^2 + B = Ax - B
<=> x^2 - Ax + 2B = 0 <=>
<=> x=[A +- sqrt(A^2 - 8B)]/2

therefore we have to analyse de root:
if A^2 - 8B < 0 - No intersection
if A^2 - 8B = 0 - One intersection
if A^2 - 8B > 0 - two intersections

To anwser the question we need to know if there is at least one inters, i.e., A^2 - 8B >=0,

Thus,
[A >= sqrt(8B) or A < -sqrt(8B) ] and b>0

Now we can only anwser depending on the info given..
Join the discussion