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Percent and Interest Problems

Expert replies
by swerve » Thu Oct 08, 2026 12:57 pm

Timer

00:00

Answers

A

B

C

D

E

Stats

Difficulty—

Did the quantity of bacteria in an experiment increase by at least \(15\%\) from 1922 to 1937?

1) The quantity of bacteria increased each year by the same percent each year from 1922 to 1937

2) The quantity of bacteria increased by at most \(1\) percent each year from 1922 to 1937

The OA is E
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Source: — Data Sufficiency |

Re: Percent and Interest Problems

by BTG Expert Team » Sun Nov 01, 2026 11:36 am
What we see: a yes or no Data Sufficiency question about growth. Did the bacteria grow by at least 15% in total from 1922 to 1937?

Step 1. Count the years and set the target.
What we see: 1922 to 1937.
What it means: that is 15 yearly increases. "At least 15%" means the final amount is at least \(1.15\) times the starting amount.
What we do and why: we check whether each statement forces the total growth above or below \(1.15\).

Step 2. Test Statement 1 alone.
What we see: the bacteria grew by the same percent every year.
What it means: we do not know that percent.
What we do and why: 10% a year gives far more than 15%, so yes. 0.1% a year gives about 1.5% in total, so no. Not sufficient.

Step 3. Test Statement 2 alone.
What we see: growth was at most 1% each year.
What it means: the yearly growth could be 1% every year, or much less.
What we do and why: try the biggest case, 1% every year: \(1.01^{15} \approx 1.161\), a 16.1% increase, so yes. Try 0.1% every year: about 1.5%, so no. Not sufficient.

Step 4. Use both statements together.
What we see: the same yearly percent \(r\), with \(r\) at most 1%.
What it means: \(r\) can still be anything from just above 0 up to 1%.
What we do and why: \(r = 1\%\) gives \(1.01^{15} \approx 1.161\), so yes. \(r = 0.5\%\) gives \(1.005^{15} \approx 1.078\), only 7.8%, so no. Two answers, so even together they are not sufficient.

The trap: choice C (or B). Many people think "1% a year for 15 years is at most 15%, so the answer is always no." Two mistakes: growth compounds, so 1% a year for 15 years is 16.1%, which passes 15%; and the rate could also be smaller.
Faster way: you do not need to work out \(1.01^{15}\). Compound growth always beats simple growth, so \(1.01^{15} > 1 + 15(0.01) = 1.15\). The top case is yes, a tiny rate is no, done.
Takeaway: growing by \(r\%\) a year for \(n\) years always gives more than \(n \times r\%\) in total, because each year's growth is taken on a bigger amount.

Answer: E
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