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Which of the following, if solved, would yield the set of all real numbers that are exactly 15 units away from -3?
A. |x + 3| = 15
B. |x - 3| = 15
C. |x - 15| = 3
D. |x + 15| = 3
E. |x + 15| = -3
OA A
Source: Veritas Prep
A. |x + 3| = 15
B. |x - 3| = 15
C. |x - 15| = 3
D. |x + 15| = 3
E. |x + 15| = -3
OA A
Source: Veritas Prep
















